Answer:
The first listed equation is the correct equation to solve
The correct answer is: t = 5 seconds
Step-by-step explanation:
Let me mention first that there is an error in the statement that the gravitational pull of the Earth is 16 ft/s^2. It is in fact 32 ft/s^2, and the actual equation uses half of the acceleration multiplied by the square of the variable time, so it gives as final expression :

and we want to find the value/s for "t" that make this equation equal zero (when it reaches the ground and the object just touches the ground. This makes the equation we want to solve:

which solving for "t" becomes:

So we adopt the positive answer (positive time) since the negative value has no physical meaning for this problem.
That is: t = 5 seconds
i hope it is helpful ti youu
Answer:
-6
Step-by-step explanation:
V = 6x + b
1/2 V -3 x = -3
V - 6x = -6
V - 6x = b
<span>a. n/4 ≤ -1
Multiply both sides by 4 => n ≤ - 4, which is all the real numbers less or equal than - 4.
That in the real number line is all the numbers to the left of - 4 (including -4)
The matching graph is the B.
b. -10n ≥ -100
Divide both sides by - 10 => n ≤ 10
That is all the real numbers less or equal than 10.
In the real number line it is all the numbers to the left of 10, including 10.
So, the matching graph is the A.
c. 5x ≥ 20
Divide both sides by 5 => x ≥ 4
That is all the real numbers greater or equal to 4.
In the real number line it is all the numbers to the right of 4, including 4.
The matching graph is C.</span>