Julianne’s displacement from her origin is equal to 10.015 kilometers.
<u>Given the following data:</u>
- Distance B = 8.5 km, Northeast.
To calculate Julianne’s displacement from her origin:
<h3>How to calculate displacement.</h3>
We would denote the two (2) unit vectors along the East and Northeast directions by i and j respectively.
<u>Note:</u> Northeast is at angle of 45° with the East.
In terms of vectors, the distances becomes:
Distance A = 2i
<u>For the </u><u>resultant displacement</u><u>:</u>
D = 10.015 kilometers.
Read more on displacement here: brainly.com/question/13416288
Answer:
Cold blooded animals are those animals that cannot regulate their body temperature and their temperature keeps changing according to their environment. ... Warm blooded animals are the animals that have a constant body temperature and can easily adapt to extreme temperatures as they can regulate their body temperature.
Answer: a) 0.78 m/s b) 1.57 m/s
Explanation:
M = father's mass
m = son's mass = M/3
V = father's initial speed
v = son's initial speed
(1/2)MV^2 = (1/2)*(1/2)*m v^2
M*V^2 = (1/2)(M/3)v^2
V^2/v^2 = 1/4
V = v/2
Second equation:
(1/2)M*(V + 1.4)^2 = (1/2)m*v^2
= (1/2)*(M/3)*(3V)^2
cancel out the M's and (1/2)'s
(V + 1.4)^2 = 3V^2
V^2 + 2.8V + 1.96 = 3V^2
V^2 -1.4V -0.98 = 0
V^2 = 0.98/0.4 = 2.45
V = 1.57
Answer:
Explanation:
In Coulomb's law the force between the charged objects depends on the distance between them which is inversely proportional to the force and the charge of the objects which is directly proportional to the force with proportional constant K.
Because q₂ is near to another charged object q₁, then, it will experience an electric force exerted by q₁.
F₁₂ = K |q₁| |q₂|/r²
= K (|-e|) (|+e|)/r²
= (9.0 x 10⁹ N.m²/C²) x (1.6 x 10⁻¹⁹ C) x (1.6 x 10⁻¹⁹ C)/ (0.80 x 10⁻⁹)²
= 3.6 x 10⁻¹⁰ N
Force F₁₂ = F₂₁
Because the two charged objects have different signs , then, the force between them will be an attractive force.
Answer:
Explanation:
Magnitude of frictional force = μ mg
μ is either static or kinetic friction.
To start the crate moving , static friction is calculated .
a ) To start crate moving , force required = μ mg where μ is coefficient of static friction .
force required =.517 x 56.6 x 9.8 = 286.76 N .
b ) to slide the crate across the dock at a constant speed , force required
= μ mg where μ is coefficient of kinetic friction , where μ is kinetic friction
= .26 x 56.6 x 9.8 = 144.21 N .