Answer:0.318 revolutions
Explanation:
Given
Initially Propeller is at rest i.e. ![\omega _0=0 rad/s](https://tex.z-dn.net/?f=%5Comega%20_0%3D0%20rad%2Fs)
after ![t=10 s](https://tex.z-dn.net/?f=t%3D10%20s)
![\omega =10 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D10%20rad%2Fs)
using ![\omega =\omega _0+\alpha t](https://tex.z-dn.net/?f=%5Comega%20%3D%5Comega%20_0%2B%5Calpha%20t)
![10=0+\alpha \cdot 10](https://tex.z-dn.net/?f=10%3D0%2B%5Calpha%20%5Ccdot%2010)
![\alpha =1 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D1%20rad%2Fs%5E2)
Revolutions turned in 2 s
![\theta =\omega _0t+\frac{\alpha t^2}{2}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%5Comega%20_0t%2B%5Cfrac%7B%5Calpha%20t%5E2%7D%7B2%7D)
![\theta =0+\frac{1\times 2^2}{2}](https://tex.z-dn.net/?f=%5Ctheta%20%3D0%2B%5Cfrac%7B1%5Ctimes%202%5E2%7D%7B2%7D)
![\theta =2 rad](https://tex.z-dn.net/?f=%5Ctheta%20%3D2%20rad)
To get revolution ![\frac{\theta }{2\pi }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctheta%20%7D%7B2%5Cpi%20%7D)
=![\frac{2}{2\pi}=0.318\ revolutions](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B2%5Cpi%7D%3D0.318%5C%20revolutions)
Air pressure is the wi get of air molecules pressing down on the earth. The pressure of the air molecules changes as you move upward from sea level into the atmosphere, the highest pressure is at sea level where the density of the air molecules is the greatest.
Colored sparks and rusting.
The speed of bullet =
850 m/s
Distance given = 1 km = 1000m
S = D/t
t • S = D/t • t
St = D
St/S = D/S
t = D/S
t = 1000m/850m/s
t = 1.176 s
It will take the bullet 1.176 or about 1.18 seconds to go 1 km.