Answer:
k = 45.95 N/m
Explanation:
First, we will find the launch speed of the ball by using the formula for the horizontal range of the projectile.
![R = \frac{v_{o}^{2}\ Sin\ 2\theta}{g} \\\\v_{o}^{2} = \frac{Rg}{Sin\ 2\theta}\\](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7Bv_%7Bo%7D%5E%7B2%7D%5C%20Sin%5C%202%5Ctheta%7D%7Bg%7D%20%5C%5C%5C%5Cv_%7Bo%7D%5E%7B2%7D%20%3D%20%5Cfrac%7BRg%7D%7BSin%5C%202%5Ctheta%7D%5C%5C)
where,
Vo = Launch Speed = ?
R = Horizontal Range = 5.3 m
θ = Launch Angle = 35°
Therefore,
![v_{o}^{2} = \frac{(5.3\ m)(9.81\ m/s^{2})}{Sin\ 2(35^{o})}\\](https://tex.z-dn.net/?f=v_%7Bo%7D%5E%7B2%7D%20%3D%20%5Cfrac%7B%285.3%5C%20m%29%289.81%5C%20m%2Fs%5E%7B2%7D%29%7D%7BSin%5C%202%2835%5E%7Bo%7D%29%7D%5C%5C)
v₀² = 55.33 m²/s²
Now, we know that the kinetic energy gain of ball is equal to the potential energy stored by spring:
![Kinetic\ Energy\ Gained\ By\ Ball = Elastic\ Potential\ Energy\ Stored\ in \ Spring\\\frac{1}{2}mv_{o}^{2} = \frac{1}{2}kx^{2}\\\\k = \frac{mv_{o}^{2}}{x^2} \\](https://tex.z-dn.net/?f=Kinetic%5C%20Energy%5C%20Gained%5C%20By%5C%20Ball%20%3D%20Elastic%5C%20Potential%5C%20Energy%5C%20Stored%5C%20in%20%5C%20Spring%5C%5C%5Cfrac%7B1%7D%7B2%7Dmv_%7Bo%7D%5E%7B2%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7Dkx%5E%7B2%7D%5C%5C%5C%5Ck%20%3D%20%5Cfrac%7Bmv_%7Bo%7D%5E%7B2%7D%7D%7Bx%5E2%7D%20%5C%5C)
where,
k = spring constant = ?
x = compression = 17 cm = 0.17 m
m = mass of ball = 24 g = 0.024 kg
Therefore,
![k = \frac{(0.024\ kg)(55.33\ m^2/s^2)}{(0.17\ m)^2} \\](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B%280.024%5C%20kg%29%2855.33%5C%20m%5E2%2Fs%5E2%29%7D%7B%280.17%5C%20m%29%5E2%7D%20%5C%5C)
<u>k = 45.95 N/m</u>
Answer:
Independent variable: how far the soccer ball is kicked.
Dependent variable: how well the person does on their math test
Explanation:
The distance the ball is kicked is what the scientist can change. On the other hand, in this experiment, how well the person does on their test supposedly relies on how far the soccer ball is kicked.
We know that whoever she is is traveling to Antarctica or elsewhere
in the south polar region. June is the beginning of Winter there, with
zero to extremely short daylight.
But we still don't know her name.
The vertical component is = vsinx m/s
If you know the angle, substitute the value of x.
If you know the velocity at which it is moving, substitute it for v
Hope it helps :)
(a) The plane makes 4.3 revolutions per minute, so it makes a single revolution in
(1 min) / (4.3 rev) ≈ 0.2326 min ≈ 13.95 s ≈ 14 s
(b) The plane completes 1 revolution in about 14 s, so that in this time it travels a distance equal to the circumference of the path:
(2<em>π</em> (23 m)) / (14 s) ≈ 10.3568 m/s ≈ 10 m/s
(c) The plane accelerates toward the center of the path with magnitude
<em>a</em> = (10 m/s)² / (23 m) ≈ 4.6636 m/s² ≈ 4.7 m/s²
(d) By Newton's second law, the tension in the line is
<em>F</em> = (1.3 kg) (4.7 m/s²) ≈ 6.0627 N ≈ 6.1 N