All categories

3 years ago

If an 80 kg is running at 2m/s, what is this man's momentum? Hint: p=mv

Physics

1 answer:

makkiz [27]3 years ago

7 0

Answer:

160kg m/s

Explanation:

momentum = mass * velocity

here given mass = 80 kg and velocity = 2m/s

so 80 * 2 = 160kg m/s

You might be interested in

An unbalanced force of 40. newtons keeps a

Pachacha [2.7K]

(4) 4.0 m/s is the correct answer

4 0

3 years ago

Read 2 more answers

Gravel is being dumped from a conveyor belt at a rate of 30 cubic feet per minute. It forms a pile in the shape of a right circu

Alona [7]

Answer:

dh/dt = 0.0566 feet / min

Explanation:

Volume per second, dV/dt = 30 cubic feet per minute

Diameter of cone = height of cone = h

at h = 15 feet, dh/dt = ?

Volume of cone is

V = πr²h

where, r be the radius of cone

According to question

radius of cone = half of diameter of cone = h /2

So,

$V=\pi \times \left ( \frac{h^{2}}{4} \right )\times h$

$V=\pi \times \frac{h^{3}}{4}$

Differentiate both sides with respect to h

$dV/dh = \frac{\pi }{4}\times 3h^{2}\times \frac{dh}{dt}$

by substituting the values

$30=\frac{3\times3.14}{4}\times 15\times 15\times \frac{dh}{dt}$

dh/dt = 0.0566 feet / min

7 0

4 years ago

What is the period of a satellite in a geosynchronous orbit?

Dominik [7]

<span>23 hours 56 minutes and 4 seconds</span>

8 0

4 years ago

(1 point) A frictionless spring with a 6-kg mass can be held stretched 0.2 meters beyond its natural length by a force of 50 new

guapka [62]

Answer:

x(t) = 0.077cos(6.455t)

Explanation:

If the spring can be stretched 0.2 m by a force of 50 N, then the spring constant is:

k = 50 / 0.2 = 250 N/m

The equation of simple harmonic motion is as the following:

$x(t) = Acos(\omega t - \phi)$

where $\omega = \sqrt{k/m} = \sqrt{250 / 6} = 6.455$

We also know that the initial velocity is 0.5 m/s, which is also the maximum speed at the equilibrium:

$v_{max} = A\omega$

$A = v_{max}/\omega = 0.5 / 6.455 = 0.077 m$

$\phi = 0$ is the initial phase

Therefore, the position of the mass after t seconds is

x(t) = 0.077cos(6.455t)

6 0

3 years ago

Water near the poles would most likely be stored as

solniwko [45]

Hey there!

Answer: Glaciers

Water near the poles would most likely be stored as glaciers. Glaciers are slow moving rivers that are a buildup of ice and snow.

Thank you!

5 0

3 years ago