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3 years ago

Does adding electrons change the mass

1 answer:

8 0

“Gaining or losing electrons has no impact on the number of protons and neutrons an atom has, which is another way of saying that the mass number is not affected by changes in the net charge.”

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A hair dryer uses 1200 watts of power. Current flow through

KonstantinChe [14]

The answer is: 120V

Power is the rate at which energy is supplied/transformed in time:
we can write:

V ddp in Volts represents Energy/Charge i.e. energy carried by each coulomb;

I current in Amperes represents Charge/time or coulombs passing each seconds.

combining them we have:

Power = energy/time = V • 1

or

1200 = V ⋅ 10
V = 1200/10 = 120V

6 0

3 years ago

Read 2 more answers

Identify each process labeled in the diagram

marishachu [46]

I am going to need a picture for this question

3 0

3 years ago

If you stood on a planet with four times the mass of Earth, and twice Earth's radius, how much would you weigh?

nikdorinn [45]

Answer:

1/4 times your earth's weight

Explanation:

assuming the Mass of earth = M

Radius of earth = R

∴ the mass of the planet= 4M

the radius of the planet = 4R

gravitational force of earth is given as = $\frac{GM}{R^{2} }$

where G is the gravitational constant

Gravitational force of the planet = $\frac{G4M}{(4R)^{2} }$

= $\frac{G4M}{16R^{2} }$

= $\frac{GM}{4R^{2} }$

recall, gravitational force of earth is given as = $\frac{GM}{R^{2} }$

∴Gravitational force of planet = 1/4 times the gravitational force of the earth

you would weigh 1/4 times your earth's weight

3 0

3 years ago

The ___ energy in a mechanical system is determined by adding the potential and kinetic enters together

Svetllana [295]

Answer:

A, total.

The total energy in a mechanical system is determined by adding the potential and kinetic enters together.

i hope this helped at all.

4 0

3 years ago

Find the moment of inertia Ihoop of a hoop of radius r and mass m with respect to an axis perpendicular to the hoop and passing

Juliette [100K]

Answer: MR²

is the the moment of inertia of a hoop of radius R and mass M with respect to an axis perpendicular to the hoop and passing through its center

Explanation:

Since in the hoop , all mass elements are situated at the same distance from the centre , the following expression for the moment of inertia can be written as follows.

I = ∫ r² dm

= R²∫ dm

MR²

where M is total mass and R is radius of the hoop .

3 0

3 years ago