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Mashcka [7]
3 years ago
11

Which of the following are considered to be a form of clastic sedimentary rock?

Physics
2 answers:
GarryVolchara [31]3 years ago
6 0
C.sand,gravel,and silt particles
umka21 [38]3 years ago
3 0

Answer:

the answer to the question is c

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In levelling, the following staff readings were observed involving an inverted staff, A = 2.915 and B = -2.028. What is the rise
salantis [7]

Answer:

The rise from A to B is 0.887

Solution:

As per the question:

The following reading of an inverted staff is given as:

A = 2.915

B = -2.028

Here, for inverted staff, the greater reading shows greater elevation and lesser reading shows lower elevation.

Thus

The rise from A to B is given as:

A - B = 2.915 - 2.028 = 0.887

8 0
3 years ago
What's a similar project to the soda and mentos project?
Lapatulllka [165]
Pop rocks and soda..... baking soda and vinegar ...
4 0
3 years ago
Read 2 more answers
If a dolphin swims at 15 m/s for 30 seconds, how far would the dolphin swim?
Olegator [25]
It would swim 30*15 metres, which is 450 metres.
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3 years ago
A rock is sitting at the edge of a flat merry-go-round at a distance of 1.6 meters from the center. The coefficient of static fr
PSYCHO15rus [73]

Answer:

ω = 2.1 rad/sec

Explanation:

  • As the rock is moving along with the merry-go-round, in a circular trajectory, there must be an external force, keeping it on track.
  • This force, that changes the direction of the rock but not its speed, is the centripetal force, and aims always towards the center of the circle.
  • Now, we need to ask ourselves: what supplies this force?
  • In this case, the only force acting on the rock that could do it, is the friction force, more precisely, the static friction force.
  • We know that this force can be expressed as follows:

       f_{frs} = \mu_{s} * F_{n} (1)

      where μs = coefficient of static friction between the rock and the merry-

      go-round surface = 0.7, and Fn = normal force.

  • In this case, as the surface is horizontal, and the rock is not accelerated in the vertical direction, this force in magnitude must be equal to the weight of the rock, as follows:
  • Fn = m*g (2)
  • This static friction force is just the same as the centripetal force.
  • The centripetal force depends on the square of the angular velocity and the radius of the trajectory, as follows:

       F_{c} = m* \omega^{2}*r (3)

  • Since (1) is equal to (3), replacing (2) in (1) and solving for ω, we get:

       \omega = \sqrt{\frac{\mu_{s} * g}{r} } = \sqrt{\frac{0.7*9.8m/s2}{1.6m}} = 2.1 rad/sec

  • This is the minimum angular velocity that would cause the rock to begin sliding off, due to that if it is larger than this value , the centripetal force will be larger that the static friction force, which will become a kinetic friction force, causing the rock to slide off.
4 0
3 years ago
Radium-226 emits alpha (α), beta (β) and gamma (γ) radiation.
Furkat [3]

Answer:

Explanation:

alpha

Alpha Radiation (α): A large, unstable nucleus decays to produce a smaller, more stable nucleus and an alpha particle (identical to a helium nucleus, ⁴₂He or ⁴₂α).

It has a very high ionizing energy and low penetrating power. It can be stopped by paper skin

Beta Radiation (β): A neutron in an unstable nucleus decays, forming a proton and emitting a beta (β) particle (identical to an electron, ⁰₋₁e or ⁰₋₁b) and resulting in a more stable nucleus.

It has high ionizing energy and penetrating power. It can be stopped by aluminium sheet

Gamma Radiation (γ): An unstable nucleus releases energy in the form of a high energy photon (no mass)to become more stable; this often accompanies other forms of radioactivity.

It has very high penetrating power and very low ionizing energy. It can be stopped by lead block.

3 0
3 years ago
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