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vfiekz [6]
3 years ago
12

The concentration of reactants or products at any time during the reaction can be calculated from the integrated rate law.

Chemistry
1 answer:
pashok25 [27]3 years ago
5 0

Answer:

True

Explanation:

Due to the fact that it is an equation that expresses the concentrations of reactants or products as a function of time, meaning that it describes the change in concentration of reactant(s) per change in time.

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What is the molarity of a 0.25-liter solution containing 52 grams of HBr? (1 point)
Pani-rosa [81]

2.6 M hBr

This would be the correct answer.

3 0
3 years ago
PLEASE HELP QUICK!! WILL MARK BRAINLIEST ANSWER!! When water is diffused across a selectively permeable membrane, scientists ref
xxTIMURxx [149]

Answer :

During diffusion, when the concentration of the molecules on both sides of the membrane is the same, the molecules will continue to move across the membrane in both the direction.

Answer 3 : It allows single-celled organism to reproduce, and other organism to repair damage tissues and grow.

Answer 4: The nucleus is an organelle that is surrounded by the cytoplasm, a jelly-like fluid.

Explanation :

Diffusion : It is a process where liquid moves from higher concentration to the lower concentration through permeable membrane.

When the concentration of the molecules on both sides of the membrane is same and the membrane is permeable membrane then diffusion will occur and the molecules will moves continuously across the membrane in both the direction.

Answer 3 :

Mitosis : It is a process of cell division. In this process, nucleus divides into two daughter cell and each daughter cell contains same number of chromosomes as present in parent nucleus.

The main purpose of the mitosis is to repair damaged tissues and growth.

Answer 4 :

Nucleus is a type of cell organelle. It is present in both animal and plant cells and it is the brain of the cell. It is present only in eukaryotic cell.

Nucleus is an organelle which is surrounded by the cell membrane which protects its from the other cells.

Cytoplasm is a jelly-like fluid which is present in the cell membrane which is made up of salt and water.


 

7 0
3 years ago
How many grams of carbonic acid were produced by the 3.00g sample of NaHCO3
Alexxx [7]
I dont know what subject is this
8 0
3 years ago
Which gas will effuse at the rate closest At a particular pressure and temperature, nitrogen gas effuses at the rate of 79mLs. U
Contact [7]

Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of nitrogen gas = 79mL/s

R_2 = rate of effusion of sulfur dioxide gas = ?

M_1 = molar mass of nitrogen gas  = 28 g/mole

M_2 = molar mass of sulfur dioxide gas = 64 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{79mL/s}{R_2})=\sqrt{\frac{64g/mole}{28g/mole}}

R_2=52mL/s

Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.

4 0
3 years ago
I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r
maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P

Now, the moles of Li3P consumed by 15 g of Al2O3:

n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP

Therefore, the total mass of products is:

m_{products}=13g+8.5g\\\\m_{products}=21.5g

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0
3 years ago
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