Question

A voltage source is connected across two 1 kohm resistors in parallel. The current flowing through the voltage source is measure by a current meter as 2 mA. What is the voltage across each resistor

Answer 1

Answer:

1 Volt

Explanation:

The resistors have resistance R = 1 kΩ each = 1 x 10^3 Ω each

The current through the voltage source I= 2 mA = 2 x 10^-3 A

The resistors are in parallel, son the total resistance will be

$\frac{1}{R_{T}}$ = $\frac{1}{R_{1}} + \frac{1}{R_{2}}$

$\frac{1}{R_{T}}$ = 1/1 kΩ  + 1/1 kΩ

$\frac{1}{R_{T}}$  = 2/1 kΩ

$R_{T}$ = 1 kΩ ÷ 2 = 0.5 kΩ = 500 Ω

From V = IR

where V is the voltage

I is the current

R is the resistance

substituting, we have

V = 500 x 2 x 10^-3 = 1 V   This is the voltage across each resistor