Question

In a typical golf swing the club is in contact with the ball for about 0.0010 s. If the .045 kg ball experiences a force of 4000 N, what is the final velocity of the golf ball?

Answer 1

Answer:

v = 88.89 [m/s]

Explanation:

To solve this problem we must use the principle of conservation of momentum which tells us that the initial momentum of a body plus the momentum added to that body will be equal to the final momentum of the body.

We must make up the following equation:

$F*t = m*v$

where:

F = force applied = 4000 [N]

t = time = 0.001 [s]

m = mass = 0.045 [kg]

v = velocity [m/s]

$4000*0.001=0.045*v\\v=88.89[m/s]$