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Dmitry_Shevchenko [17]
3 years ago
14

In a typical golf swing the club is in contact with the ball for about 0.0010 s. If the .045 kg ball experiences a force of 4000

N, what is the final velocity of the golf ball?
Physics
1 answer:
Musya8 [376]3 years ago
5 0

Answer:

v = 88.89 [m/s]

Explanation:

To solve this problem we must use the principle of conservation of momentum which tells us that the initial momentum of a body plus the momentum added to that body will be equal to the final momentum of the body.

We must make up the following equation:

F*t = m*v

where:

F = force applied = 4000 [N]

t = time = 0.001 [s]

m = mass = 0.045 [kg]

v = velocity [m/s]

4000*0.001=0.045*v\\v=88.89[m/s]

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