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Veronika [31]
3 years ago
10

A town has two malls. 62% of the town’s residents shop at Willow Creek Mall. 73% of the residents shop at Two Harbors Mall. 48%

of the residents visit both malls. On any given day, what is the probability that a person chosen at random will visit either Willow Creek or Two Harbors?
A. 0.87
B. 0.64
C. 0.62
D. 0.75
E. 0.48
Mathematics
1 answer:
alekssr [168]3 years ago
6 0
I believe the correct answer is A. 0.87
  On any given day, the probability that a person chosen at random will visit either Willow Creek or Two Harbors is <span>0.87

How did I get this?
 62% = 0.62    73% = 0.73   48% = 0.48
 
( 0.62 + 0.73 ) - 0.48
  *Sorry had to correct it I did the math again and got 0.87*</span>
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What is 1/5 + 1/2 in a fraction<br>​
Bezzdna [24]

Answer:

7/10

Step-by-step explanation:

first you find a common denominator which would be 10 so you turn 1/5 into 2/10 and 1/2 into 5/10 and then add 2/10 + 5/10 =7/10

4 0
3 years ago
Read 2 more answers
2. The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.
Paul [167]
For this case we have an equation of the form:
 h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
 Where,
 vo: initial speed
 a: acceleration:
 h0: initial height.
 We have the following equation:
 h (t) = - 16t2 + 19t + 110
 Therefore, the initial velocity is:
 vo = 19 feet / s
 Answer:
 
The initial velocity when the rock is thrown:
 
vo = 19 feet / s
8 0
3 years ago
Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

5 0
3 years ago
Please help me with this question
dmitriy555 [2]

if any doubt leave a comment

3 0
2 years ago
Simplify y+1&lt;3 please need help
Zepler [3.9K]
STEP-BY-STEP SOLUTION:

Let's first establish the inequality which we need to solve as displayed below:

y + 1 < 3

To begin with, we need to make ( y ) the subject by keeping it on the left-hand side of the inequality and placing all other numbers on the right-hand side of the equality as displayed below:

y + 1 < 3

y < 3 - 1

Then, we simply simplify / solve as displayed below:

y < 3 - 1

y < 2

ANSWER:

y < 2
4 0
3 years ago
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