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KatRina [158]
3 years ago
13

A sandbox is being built in a park. The diagram shows the four vertices of the sandbox. Each unit in the

Mathematics
1 answer:
____ [38]3 years ago
5 0

Answer:

the answer is 90 square feet.

Step-by-step explanation:

the length is 10, and the height is 9.

10×9=90

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Solve for x. Show your work with proper statements and notation.
9966 [12]

Answer:

x = 26

Step-by-step explanation:

The sum of the angles around point O = 360°, thus

x + 3x + 256 = 360 , that is

4x + 256 = 360 ( subtract 256 from both sides )

4x = 104 ( divide both sides by 4 )

x = 26

4 0
3 years ago
A group of 6 students was playing a game. Each student had a score of -90 at the end of the first round. What was the total of t
Butoxors [25]

Answer:

it means poop

Step-by-step explanation:

8 0
3 years ago
Distributing property and combining like terms <br> -10(1-3x)-10
ikadub [295]

Answer:

-20 + 30x

Step-by-step explanation:

-10(1) = -10

-10(-3x) = 30x

new equation

-10 + 30x -10

-10 + -10 = -20

-20 + 30x

7 0
3 years ago
Lf x+1/x=12 then find the value of x3+1/x3​
Tresset [83]
Answer:

Explanation:

First we find what x is:
x + 1/x = 12
x + 1 = 12x
1 = 12x - x
1 = 11x
1/11 = x
Or x = 1/11

Plug x value in x^3 + 1/x^3

(1/11)^3 + 1/(1/11)^3
= (1^3/11^3)+ 1/(1^3/11^3)
= (1/1331 + 1)/1/1331
= (1/1331 + 1331/1331)/1/1331
= 1332/1331 x 1331/1
= 1332/1
= 1332

Therefore, x^3 + 1/x^3 = 1332
4 0
3 years ago
To solve a system of inequalities, you just need to graph each inequality and see wich points are in the overlap of the graphs.
GrogVix [38]
<h3>Answer: True</h3>

This is often how many math teachers and textbooks approach problems like this. The overlapped region is the region in which satisfies every inequality in the system. Be sure to note the boundary of each region whether you're dealing with a dashed line or a solid line. Dashed lines mean points on the boundary do not count as solution points, whereas solid boundaries allow those points as part of the solution set.

Side note: This is assuming you're dealing with 2 variable inequalities. If you only have one variable, you don't need to graph and instead could use algebra. Graphing doesn't hurt though.

3 0
3 years ago
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