Question

write the condensed, complete, and net ionic equations for any reaction that occurs between K2CrO4(aq) and Fe(NO3)3(aq).

Answer 1

Answer:

Condensed equation:  $3K_2CrO_4(aq)+2Fe(NO_3)_3(aq)\rightarrow Fe_2(CrO_4)_3(s)+6KNO_3(aq)$

Complete ionic equation : $6K^+(aq)+3CrO_4^-(aq)+2Fe^{2+}(aq)+6NO_3^-(aq)\rightarrow Fe_2(CrO_4)_3(s)+6K^+(aq)+6NO_3^-(aq)$

Net ionic equation :   $3CrO_4^-(aq)+2Fe^{2+}(aq)\rightarrow Fe_2(CrO_4)_3(s)$

 Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

The balanced chemical equation is:

$3K_2CrO_4(aq)+2Fe(NO_3)_3(aq)\rightarrow Fe_2(CrO_4)_3(s)+6KNO_3(aq)$

Condensed equation : $3K_2CrO_4(aq)+2Fe(NO_3)_3(aq)\rightarrow Fe_2(CrO_4)_3(s)+6KNO_3(aq)$

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

$6K^+(aq)+3CrO_4^-(aq)+2Fe^{2+}(aq)+6NO_3^-(aq)\rightarrow Fe_2(CrO_4)_3(s)+6K^+(aq)+6NO_3^-(aq)$

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.  Spectator ions are the ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

$3CrO_4^-(aq)+2Fe^{2+}(aq)\rightarrow Fe_2(CrO_4)_3(s)$