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3 years ago

why is often necessary to follow extensive purification procedures in the isolation of organic compounds?

Chemistry

1 answer:

GREYUIT [131]3 years ago

6 0

To remove impurities

<u>Explanation:</u>

There are different substances present in an organic compound. If an organic compound contains different substances then there are some physical or chemical methods for the process of isolation, so that we will get different substances from the organic compound, which may or may not contain impurities.
To get rid of impurities after the isolation process purification process has to be done, so that we will get a purified substance from an organic compound.
Purification may be done using the method of sublimation, distillation and so on.

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Consider 5.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.30 L and the temperature is increased to 4

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Answer:

P₂ = 1.12 atm

Explanation:

To find the new pressure, you need to use the Combined Gas Law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the new pressure, volume, and temperature. Before plugging the values into the equation, you need to

(1) convert the pressure from mmHg to atm (760 mmHg = 1 atm)

(2) convert the temperatures from Celsius to Kelvin (°C + 273)

The final answer should have 3 sig figs like the given values.

P₁ = 365 mmHg / 760 = 0.480 atm P₂ = ? atm

V₁ = 5.00 L V₂ = 2.30 L

T₁ = 20°C + 273 = 293 K T₂ = 40°C + 273 = 313 K

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$ <----- Combined Gas Law

$\frac{(0.480 atm)(5.00 L)}{293 K}=\frac{P_2(2.30 L)}{313 K}$ <----- Insert values

$0.00819=\frac{P_2(2.30 L)}{313 K}$ <----- Simplify left side

$2.56 = P_2(2.30L)$ <----- Multiply both sides by 313

$1.12 = P_2$ <----- Divide both sides by 2.30

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1 year ago

What is the mass of 3.45 moles<br> NO2?<br> (N = 14.01 g/mol, O = 16.00 g/mol)

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Answer:

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3 years ago

The molar heat capacity of a compound with the formula C2H6SO is 88.0 J/mol-K. The specific heat of this substance is __________

lisabon 2012 [21]

Answer : The specific heat of this substance is, 1.13 J/g.K

Explanation :

Molar heat capacity : It is defined as the amount of heat absorbed by one mole of a substance to raise its temperature by one degree Celsius.

As we are given that the chemical formula of compound is, $C_2H_6SO$

First we have to calculate the molar mass of given compound.

Molar mass of $C_2H_6SO$ = $2(12g/mol)+6(1g/mol)+32g/mol+16g/mol$

Molar mass of $C_2H_6SO$ = 78 g/mol

Now we have to calculate the specific heat of this substance.

Specific heat of this substance = $\frac{\text{Molar heat capacity of a compound}}{\text{Molar mass of }C_2H_6SO}$

Specific heat of this substance = $\frac{88.0J/mol.K}{78g/mol}$

Specific heat of this substance = 1.13 J/g.K

Thus, the specific heat of this substance is, 1.13 J/g.K

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3 years ago

Give a term for each description.Organic chemicals that can vaporize into the air.Secondary chemicals whose formation is facilit

Phantasy [73]

Answer:

Volatile organic compounds
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Explanation:

Volatile organic compounds are the organic chemicals that get easily vaporized in air.

The secondary chemicals or the secondary pollutants are the photochemical substances that are formed in the presence of sunlight.

The amount of gases and small particles present in the atmosphere, responsible for influencing ecosystem and the wellness of human beings is known as the Air Quality

Air pollution refers to the high concentrations of gases or small particles that are present in the atmosphere, which can cause harm to the humans and other living organisms and structures established by humans.

Aerosols are the tiny particles present in liquid or solid state, that are suspended in air.

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3 years ago

why is often necessary to follow extensive purification procedures in the isolation of organic compounds?​

why is often necessary to follow extensive purification procedures in the isolation of organic compounds?