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klio [65]
2 years ago
12

N2 (g) + __ H2 (g) --> _NH3 When the reaction above is completely

Chemistry
1 answer:
Advocard [28]2 years ago
7 0

Answer:

3

Explanation:

left side has 2 N so right side must have a 2 which means 6 H on right side so to get 6 on left you have a coef. of 3 to make 6 H

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You determine the volume of your plastic bag (simulated human stomach) is 1.08 L. How many grams of NaHCO3 (s) are required to f
dsp73

Answer:

3.636 grams of sodium bicarbonate is required.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 753.5 mmHg = 0.9914 atm

(1 atm = 760 mmHg)

V = Volume of gas = 1.08 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 24.5 °C= 297.65  K

Putting values in above equation, we get:

(0.9914 atm)\times 1.08 L=n\times (0.0821L.atm/mol.K)\times 297.65K\\\\n=0.0438 mole

Percentage recovery of carbon dioxide gas =  49.4%

Actual moles of carbon dioxide formed: 49.4% of 0.0438 mole

\frac{49.4}{100}\times  0.0438 mol=0.02164 mol

2NaHCO_3\righarrow Na_2CO_3+H_2O+CO_2

According to reaction ,1 mol is obtained from 2 moles of sodium bicarbonate.

Then 0.02164 moles f carbon dioxide will be obtained from:

\frac{2}{1}\times 0.02164 mol=0.04328 mol

Mass of 0.04328 moles pf sodium bicarbonate:

0.04328 mol × 84 g/mol = 3.636 g

3.636 grams of sodium bicarbonate is required.

5 0
3 years ago
what gas was given off when hydrogen peroxide is broken down? recall that the formula for hydrogen peroxide is h2o2?
Anna35 [415]
When hydrogen peroxide is broken down the gas released or given off is Oxygen. 
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3 years ago
An object that has a height of 0.4 meter is placed at a distance of 0.7 meter from a concave spherical mirror. An image is forme
julia-pushkina [17]

Answer: B. 0.6125 m

For spherical concave mirror:

Height of the object, h_o=0.4\hspace{1mm}m

Height of the image, h_i=0.35\hspace{1mm}m

Object distance, u=-0.7 m

we need to find the distance of the image, v.

These are related by the following formula:

\frac{h_i}{h_o}=-\frac{v}{u}\\ \Rightarrow v=u\times\frac{h_i}{h_o}

Insert the values:

v=-(-0.7\times\frac{0.35}{0.4})=0.6125\hspace{1mm}m

Hence, option B is the correct.


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3 years ago
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It is b or a check with someone else
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What amount of energy is required to change a spherical drop of water with a diameter of 1.60 mm to five smaller spherical drops
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72.0 ok hope this helps


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