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saul85 [17]
2 years ago
9

Forces that act in equal and opposite directions on an object

Physics
1 answer:
Akimi4 [234]2 years ago
5 0
These are known as balanced forces because they will not change the motion of the object, and it will remain at rest unless forces become unbalanced- meaning they would be unequal and not opposing. 
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Sunspots appear dark because they are cooler than the surrounding solar surface. True or false
DiKsa [7]

Answer:

False, Sunspots appear dark (in visible light) due to their low temperature(cooler) than rest of the sun

Explanation:

Sunspots appear dark because they are much cooler( have low temperature than the rest of the surface contained by Sun. As they appear dark, but still they have very temperature that's why so hot. Sunspots have temperatures ranges  3,500 Celsius (3773 kelvin) and the surrounding surface of the sun has a temperature much higher of about 5,500 Celsius(5773 Kelvin). Even if we see a sunspot alone in space,  it will glow so brightly.

Learn more about sunspots :

brainly.com/question/27774496

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6 0
1 year ago
What a measurement? Write down t its importance inn an our daily life.​
balu736 [363]

Answer:

Time, size, distance, speed, direction, weight, volume, temperature, pressure, force, sound, light, energy—these are among the physical properties for which humans have developed accurate measures, without which we could not live our normal daily lives. Measurement permeates every aspect of human life.

8 0
3 years ago
Which statement best describes how electric fields and magnetic fields are alike?
gladu [14]
<span>Electric field repulsive for objects of like charge and attractive for opposite type of charges and for a magnet you can say that like poles repel and unlike attracts so D makes sense</span>
3 0
3 years ago
Assume that the loop is initially positioned at θ=30∘θ=30∘ and the current flowing into the loop is 0.500 AA . If the magnitude
labwork [276]

Answer:\tau=1.03\times 10^{-4}\ N-m

Torque,

Explanation:

Given that,

The loop is positioned at an angle of 30 degrees.

Current in the loop, I = 0.5 A

The magnitude of the magnetic field is 0.300 T, B = 0.3 T

We need to find the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field. We know that the torque is given by :

\tau=NIAB\ \sin\theta

Let us assume that, A=0.0008\ m^2

\theta is the angle between normal and the magnetic field, \theta=90^{\circ}-30^{\circ}=60^{\circ}

Torque is given by :

\tau=1\times 0.5\ A\times 0.0008\ m^2\times 0.3\ T\ \sin(60)\\\\\tau=1.03\times 10^{-4}\ N-m

So, the net torque about the vertical axis is 1.03\times 10^{-4}\ N-m. Hence, this is the required solution.

4 0
2 years ago
A meteoroid is moving towards a planet. It has mass m = 0.78×109 kg and speed v1 = 4.1×107 m/s at distance R1 = 2.8×107 m from t
wariber [46]

Answer:

PE=81.755\, J

Explanation:

Given that:

  • mass of meteoroid, m=7.8\times 10^8 \,kg
  • radial distance from the center of the planet, R= 2.8\times 10^7 m
  • mass of the planet, M=4.4\times 10^{25}\, kg

<u>For gravitational potential energy we have:</u>

PE=G\frac{M.m}{R}

substituting the respective values:

PE=6.67\times 10^{-11}\times \frac{4.4\times 10^{25}\times 7.8\times 10^8}{2.8\times 10^7}

PE=81.755\, J

5 0
3 years ago
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