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marta [7]
3 years ago
9

5. The ends of a 10 cm laser rod, index of refraction = 1.76, has its ends coated for reflectivity of 99.9 % and 90 %. If there

is no excited state absorption (  calculate a) the fractional loss per pass and b) the decay time of the cavity
Physics
1 answer:
Jobisdone [24]3 years ago
3 0

Answer:

the fractional loss per pass =0.053

the decay time of the cavity =11 ns

Explanation:

laser is an acronym for Light Amplification by Stimulated Emission of Radiation and it has lot of military applications : basically ranging from target acquisition, fire control, and training. It is also being used  in LIDAR communications, radar systems , laser guided landing systems, laser pointers, holography, photography, guidance systems, scanning machines, metal working,  and medicine.

the fractional loss per pass= \alpha l - ln(R_1R_2)^ \frac {1}{2}

but no excited state absorption, therefore \alpha is 0

= - ln(R_1R_2)^ \frac {1}{2}\\\\=- ln(0.999* 0.9)^ \frac {1}{2}

=0.053

b) the decay time of the cavity:

T_c = \frac{nd}{cl_f}=\frac{1,76 * 10 *10^-2}{3 *10^8 *0.53}

=1.1 *10^-8 seconds

=11 ns

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iragen [17]

The Moment of Inertia of the Disc is represented by I = \frac{15}{32}\cdot M\cdot R^{2}. (Correct answer: A)

Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:

I = I_{D} - I_{H} (1)

Where:

  • I_{D} - Moment of inertia of the Disk.
  • I_{H} - Moment of inertia of the Hole.

Then, this formula is expanded as follows:

I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right) (1b)

Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole (m):

\frac{m}{M} = \frac{R^{2}}{4\cdot R^{2}}

m = \frac{1}{2}\cdot M

And the resulting equation is:

I = \frac{1}{2}\cdot M\cdot R^{2} -\frac{1}{2}\cdot \left(\frac{1}{4}\cdot M \right) \cdot \left(\frac{1}{4}\cdot R^{2} \right)

I = \frac{1}{2} \cdot M\cdot R^{2} - \frac{1}{32}\cdot M\cdot R^{2}

I = \frac{15}{32}\cdot M\cdot R^{2}

The moment of inertia of the Disc is represented by I = \frac{15}{32}\cdot M\cdot R^{2}. (Correct answer: A)

Please see this question related to Moments of Inertia: brainly.com/question/15246709

5 0
2 years ago
Suppose that the acceleration of a model rocket is proportional to the difference between 100 ft/sec and the rocket's velocity.
sp2606 [1]

Answer:

Explanation:

initial velocity, u = 0

final velocity, v = 80 ft/s

acceleration, a = 150 ft/s²

Let the time taken is t.

v = u + at

80 = 0 + 150 x t

t = 0.53 second

3 0
3 years ago
A 72.9-kg base runner begins his slide into second base when moving at a speed of 4.02 m/s. The coefficient of friction between
elena-14-01-66 [18.8K]

Answer:

-589.05 J

Explanation:

Using work-kinetic energy theorem, the work done by friction = kinetic energy change of the base runner

So, W = ΔK

W = 1/2m(v₁² - v₀²) where m = mass of base runner = 72.9 kg, v₀ = initial speed of base runner = 4.02 m/s and v₁ = final speed of base runner = 0 m/s(since he stops as he reaches home base)

So, substituting the values of the variables into the equation, we have

W = 1/2m(v₁² - v₀²)

W = 1/2 × 72.9 kg((0 m/s)² - (4.02 m/s)²)

W = 1/2 × 72.9 kg(0 m²/s² - 16.1604 m²/s²)

W = 1/2 × 72.9 kg(-16.1604 m²/s²)

W = 1/2 × (-1178.09316 kgm²/s²)

W = -589.04658 kgm²/s²

W = -589.047 J

W ≅ -589.05 J

4 0
2 years ago
Suppose that two objects attract each other with a gravitational force of 16 units. If the distance between the two objects is r
Naddik [55]

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant throughout the universe.

D is the distance between both objects.

D is now reduced by a factor of 5, meaning Dnew = D/5 we get

Fgravitynew = G*(mass1*mass2)/(D/5)² =

= G*(mass1*mass2)/(D²/25) =

= 25* G*(mass1*mass2)/D² = 25* Fgravity

the new force of gravity/attraction is 25×16 = 400 units.

4 0
2 years ago
Qual o valor a ser pago, no final de 5 meses e 18 dias, correspondente a um empréstimo de $125.000,00, sabendo-se que a taxa de
liberstina [14]
25% ao semestre = 25%/6 ao mes.
Um mes tem em media 365/12 dias, ou 30,42 dias/mes.
18 dias = 18/30,42 mes

5 meses + 18 dias = 5 meses + 18/30,42 mes = 5,592 mes

a taxa de juros por 5 meses e 18 dias e 25%/6 * 5.592 = 23,3%

123,3% * $125.000 = $154.125,00
6 0
3 years ago
Read 2 more answers
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