All categories

3 years ago

PLEASE HELP ME

Physics

1 answer:

RoseWind [281]3 years ago

5 0

KE = ½ m v^2
so it depends on its speed (and mass)

You might be interested in

What is the effect on climate from these factors??

fenix001 [56]

The effect on the climate is that the climate goes up

7 0

4 years ago

Two resistors of 12Ω and 2Ω are connected in parallel to a battery of 4 V. Current through 12Ω resistor will be _____________ an

Alex

Answer:

0.33 Amp

8 Watts

Explanation:

The current through the 12 Ω resistor will be given by Ohm's law:

4 V / 12 Ω = 1/3 Amp ≈ 0.33 Amp

The power dissipated on the 2 Ω resistor can be calculated via the formula: $\frac{V^2}{R}$ which gives:

4^2 / 2 = 8 Watts

6 0

3 years ago

Juan is making ice tea. When he adds ice to the tea, why does the tea cool down?

Tresset [83]

Answer: because the ice was cold, and it melted in the tea. So the tea is now cooler.

Explanation:

4 0

3 years ago

The fastest pitched baseball was clocked at 46 m/s. assume that the pitcher exerted his force (assumed to be horizontal and cons

Zielflug [23.3K]

Using the Equation:
v² = vi² + 2 · a · s → Eq.1
where,
v = final velocity
vi = initial velocity
a = acceleration
s = distance

We know that vi = 0 because the ball was at rest initially.

Therefore,

Solving Eq.1 for acceleration,

 v² = vi² + 2 · a · s
v² = 0 + 2 · a · s
v² = 2 · a · s
Rearranging for a,
a = v ²/2·s
Substituting the values,
a = 46²/2×1
a = 1058 m/s²

Now applying Newton's 2nd law of motion,

F = ma
= 0.145×1058

F = 153.4 N

8 0

3 years ago

A 12,000kg. railroad car is traveling at +2m/s when it

ivann1987 [24]

Answer:

The final velocity of the two railroad cars is 1.09 m/s

Explanation:

Since we are given that the two cars lock together it shows that the collision is inelastic in nature. The final velocity due to inelastic collision is given by

$\mathrm{V}=\frac{V 1 M 1+V 2 M 2}{M 1+M 2}$

where

V= Final velocity

M1= mass of the first object in kgs = 12000

M2= mas of the second object in kgs = 10000

V1= initial velocity of the first object in m/s = 2m/s

V2= initial velocity of the second object in m/s = 0 (given at rest)

Substituting the given values in the formula we get

V = 2×12000 + 0x100012000 + 10000= 2400022000= 1.09 m/s

$\mathrm{V}=\frac{2 \times 1200+0 \times 1000}{12000+10000}=\frac{24000}{22000}=1.09 \mathrm{m} / \mathrm{s}$

Which is the final velocity of the two railroad cars

8 0

3 years ago

﻿﻿PLEASE HELP ME

PLEASE HELP ME