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coldgirl [10]
4 years ago
15

Why do objects that are thrown or shot follow a curved path

Physics
1 answer:
LenaWriter [7]4 years ago
8 0
The initial force of the throw overcomes gravity quite easily. Then, gravity begins to bring it back down to earth, making a curved path.

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A person drops a 2.00 kg ball off a building. what is the force of weight on the ball?
Lostsunrise [7]

Explanation:

Given

mass (m) = 2 kg

acceleration due to gravity (g) = 10 m/s²

Force (F) = ?

We know

F = m * a

= 2 * 10

= 20 N

The force is 20 N.

Hope it will help :)❤

8 0
3 years ago
The kettle is filled with 5.0 kg of water at 20 °C. The specific heat capacity of water = 4 200 J/Kg °C. Calculate the energy ne
Allisa [31]

Answer:

17 * 10^5 J

Explanation:

From;

H= mcΘ

where;

m = mass of water = 5.0 Kg

c = heat capacity of water = 4 200 J/Kg °C

Θ = temperature rise = 100 °C - 20 °C = 80°C

Substituting values;

H = 5 * 4 200 * 80

H = 17 * 10^5 J

4 0
3 years ago
What subatomic particle determines the identity of an element
FinnZ [79.3K]

Answer:

Proton

Explanation:

Proton is a subatomic particle and determines the identity of an element. each element is identified by its atomic number. In an element, the number of protons in the nuclei of the atoms of the element is same as the atomic number of that element and this number is different for each element. for example, Boron has 5 protons in its nuclei, hence the atomic number of the element is 5.

3 0
3 years ago
An object weighs 60.0 kg on the surface of the earth. How much does it weigh 4R from the surface? (5R from the center)
Alecsey [184]
"60 kg" is not a weight.  It's a mass, and it's always the same
no matter where the object goes.

The weight of the object is   

                                 (mass) x (gravity in the place where the object is) .

On the surface of the Earth,

                   Weight = (60 kg) x (9.8 m/s²)

                                =      588 Newtons.

Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to  5R  from the center, the gravity out there is

                    (1R/5R)²  =  (1/5)²  =  1/25  =  0.04 of its value on the surface.

The object's weight would also be 0.04 of its weight on the surface.

                 (0.04) x (588 Newtons)  =  23.52 Newtons.

Again, the object's mass is still 60 kg out there.
___________________________________________

If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
60 kilograms, then you should be raising a holy stink. 
You are being planted with sloppy, inaccurate, misleading
information, and it's going to be YOUR problem to UN-learn it later.
They owe you better material.
6 0
3 years ago
What is necessary condition for the conservation of momentum?
MrRa [10]
N<span>o net external force acts on the system </span>
6 0
3 years ago
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