Answer:
(a) t = 1.67 s
(b) s₂ = 45 m
Explanation:
Here, we use the formula:
s = vt
FOR Seth:
s₁ = v₁t₁
where,
s₁ = distance covered by Seth
v₁ = speed of Seth = 9 m/s
t₁ = time taken by Seth
FOR Mack:
s₂ = v₂t₂
where,
s₂ = distance covered by Mack
v₂ = speed of Mack = 27 m/s
t₂ = time taken by Mack
since, initially Mack is 30 m behind Seth. Therefore,
(a)
s₂ = s₁ + 30 m
using formulae:
v₂t₂ = v₁t₁ + 30 m
but, the time of catching is same for both (t₁ = t₂ = t)
v₂t = v₁t + 30 m
using values:
(27 m/s)t - (9 m/s)t = 30 m
t = (30 m)/(18 m/s)
<u>t = 1.67 s</u>
(b)
s₂ = v₂t
using values:
s₂ = (27 m/s)(1.67 s)
<u>s₂ = 45 m</u>
Answer:
14.16 W
Explanation:
We have given impedance Z=91.5 ohm
Voltage across the resistor = 36 V
We have to find the power delivered by the source
We know that according to telegens theorem , the absorbed = power delivered
So the voltage across the resistor = 36 V
Current in the RLC circuit 
this current will be same in the whole circuit as it is a series RLC circuit
Now the power absorbed by the resistor 
As the power absorbed = power delivered
So power delivered by the source =14.16 W
From the curve on the graph we can see, when y=50 x=4.5
the unit of x-axis is in "billions of years", so the answer is 4.5 billions of years
Hey! So referring to the data the thing we can clearly see is that in a vacuum, everything, regardless of its mass, falls at the same speed.
Acceleration is often confused with speed, or velocity, but the difference is, acceleration by definition is the rate of which an object falls with respect to its mass and time.
Every single thing in the world falls at the same acceleration, this is because of gravity. The difference is the speed of which it falls. In space, there is not any gravity, and so, the objects are able to fall at the same speed regardless of their mass.
Answer:
The railroad tracks are 13 m above the windshield (12 m without intermediate rounding).
Explanation:
First, let´s calculate the time it took the driver to travel the 27 m to the point of impact.
The equation for the position of the car is:
x = v · t
Where
x = position at time t
v = velocity
t = time
x = v · t
27 m = 17 m/s · t
27 m / 17 m/s = t
t = 1.6 s
Now let´s calculate the distance traveled by the bolt in that time. Let´s place the origin of the frame of reference at the height of the windshield:
The position of the bolt will be:
y = y0 + 1/2 · g · t²
Where
y = height of the bolt at time t
y0 = initial height of the bolt
g = acceleration due to gravity
t = time
Since the origin of the frame of reference is located at the windshield, at time 1.6 s the height of the bolt will be 0 m (impact on the windshield). Then, we can calculate the initial height of the bolt which is the height of the railroad tracks above the windshield:
y = y0 + 1/2 · g · t²
0 = y0 -1/2 · 9.8 m/s² · (1.6 s)²
y0 = 13 m
