Answer:
<em><u>0</u></em><em><u>.</u></em><em><u>9</u></em><em><u>1</u></em>
Explanation:
as equivalence resistance can be found out using the
1/Req = 1/r1 +1/r2 +1/r3......
now, 1/req= 1/2+1/3+1/4
=6/12+4/12+3/12
=13/12
i.e, req =12/13 =0.91
✌️:)
Answer:
The acceleration of the spacecraft is 16,367.62 miles/hr²
Explanation:
Given;
thrust of the spacecraft, F = 5.31 x 10⁶ N
mass of the spacecraft, m = 5,760,000 lbm = 2612692.051 kg
The acceleration of the spacecraft in m/s² is given by Newton's second law of motion;
F = ma
a = F / m
The acceleration in miles per hour square is given by;
Therefore, the acceleration of the spacecraft is 16,367.62 miles/hr²
Answer:
6.74 m
Explanation:
PE = KE
mgh = 1/2 mv^2
30 ( 9.81) h = 1/2 (30)(11.5)^2
h = 6.74 m
Answer:3.92475J
Explanation:
ideal gas equation
PV=nrT
P=pressure
V=volume 9*5*14=630m^3
n=mole
Mole=mass/molecular mass
molecular mass of air=28.1g/mol
R=gas constant
T=temperature in kelvin
1.01*10^5*630=(m/28)*8.314j/molK *273K
784959.5677356082g
784.95kg
Kinetic energy=0.5*m*v^2
Velocity of air
0.5*784.95kg*0.1^2
K.E=3.92475J
6
Then, it's speed must be increased by 4 times.
As we know, K.E. α v²