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2 years ago

Naruto is running towards Zetsu. Starting from rest, he accelerates to a velocity of 15

Physics

1 answer:

Angelina_Jolie [31]2 years ago

8 0

Answer:

1.2 m/s^2

Explanation:

average acceleration = vf-vi/t = (15 m/s-0 m/s)/10 s = 1.2 m/s^2

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What is the name given to a material with zero resistance that can conduct electricity without a loss of energy?

tatyana61 [14]

It would be C. Superconductor

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3 years ago

Is a cinder cone volcanoe constructive or deconstructive

Ksivusya [100]

Cinder cone volcanoes can be associated with either constructive or destructive margins.

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3 years ago

¿Cuantos metros recorre una motocicleta en un segundo si circula a una velocidad de 90km/h?

Zina [86]

Answer:

La motocicleta recorre 25 metros en 1 segundo si circula a una velocidad de 90 km/h

Explanation:

La velocidad es una magnitud que expresa el desplazamiento que realiza un objeto en una unidad determinada de tiempo, esto es, relaciona el cambio de posición (o desplazamiento) con el tiempo.

Siendo la velocidad es el espacio recorrido en un período de tiempo determinado, entonces 90 km/h indica que en 1 hora la motocicleta recorre 90 km. Entonces, siendo 1 h= 3600 segundos (1 h=60 minutos y 1 minuto=60 segundos) podes aplicar la siguiente regla de tres: si en 3600 segundos (1 hora) la motocicleta recorre 90 km, entonces en 1 segundo ¿cuánta distancia recorrerá?

$distancia=\frac{1 segundo*90 km}{3600 segundos}$

distancia= 0.025 km

Por otro lado, aplicas la siguiente regla de tres: si 1 km es igual a 1,000 metros, ¿0.025 km cuántos metros son?

$distancia=\frac{0.025 km*1,000 metros}{1 km}$

distancia= 25 metros

La motocicleta recorre 25 metros en 1 segundo si circula a una velocidad de 90 km/h

6 0

3 years ago

A runner of mass 56.0kg runs around the edge of a horizontal turntable mounted on a vertical, frictionless axis through its cent

SCORPION-xisa [38]

Answer: -0.84 rad/sec (clockwise)

Explanation:

Assuming no external torques act on the system (man + turntable), total angular momentum must be conserved:

L1 = L2

L1 = It ω + mm. v . r = 81.0 kg . m2 .21 rad/s – 56.0 kg. 3.1m/s . 3.1 m

L1 = -521.15 kg.m2/sec (1)

(Considering to the man as a particle that is moving opposite to the rotation of the turntable, so the sign is negative).

Once at rest, the runner is only a point mass with a given rotational inertia respect from the axis of rotation, that can be expressed as follows:

Im = m. r2 = 56.0 kg. (3.1m)2 = 538.16 kg.m2

The total angular momentum, once the runner has come to an stop, can be written as follows:

L2= (It + Im) ωf = -521.15 kg.m2/sec

L2= (81.0 kg.m2 + 538.16 kg.m2) ωf = -521.15 kg.m2/sec

Solving for ωf, we get:

ωf = -0.84 rad/sec (clockwise)

5 0

2 years ago

I NEED HELP PLZ. can some one explain partial variation

dezoksy [38]

Answer:

Explanation:

Partial Variation is a relation that is of the form y = mx+b. The graph of y = mx+b is a straight line with the slope of m and a y-intercept of b. ... The relation y = mx +b represents partial variation because the value of y varies partially with the value of x.

8 0

2 years ago