All categories

2 years ago

How are people responsible for marine debris

Chemistry

1 answer:

Pepsi [2]2 years ago

5 0

Answer:

Marine debris comes from many different sources and enters the ocean in many ways. Intentional littering and dumping are a big cause of marine debris. ... Those rivers and streams can eventually carry the trash to the ocean. Improper or careless waste disposal is another big cause.

hope this helps

have a good day :)

Explanation:

You might be interested in

Explain why Nitrogen -17 is unstable

Yuri [45]

Has only 7 electrons so it want to bond with other elements so its very reactive and unstable. Hope this helps

4 0

1 year ago

Hydrazine, N2H4, is a corrosive liquid used in rocket and jet fuels. Ammonia, NH3, is a gas that dissolves in water to form a so

Lyrx [107]

OK in the case of hydrazine 14 grams of nitrogen combine with 2 gram of hydrogen and with ammonia 14 grams combine with 3 grams of hydrogen.

Ratio 2:3

5 0

3 years ago

Indicate the peptides that would result from cleavage by the indicated reagent: a. Gly-Lys-Leu-Ala-Cys-Arg-Ala-Phe by trypsin b.

Ilia_Sergeevich [38]

Answer:

a. Gly-Lys + Leu-Ala-Cys-Arg + Ala-Phe

b. Glu-Ala-Phe + Gly-Ala-Tyr

Explanation:

In this case, we have to remember which peptidic bonds can break each protease:

-) Trypsin

It breaks selectively the peptidic bond in the carbonyl group of lysine or arginine.

-) Chymotrypsin

It breaks selectively the peptidic bond in the carbonyl group of phenylalanine, tryptophan, or tyrosine.

With this in mind in "peptide a", the peptidic bonds that would be broken are the ones in the "Lis" and "Arg" (See figure 1).

In "peptide b", the peptidic bond that would be broken is the one in the "Phe" (See figure 2). The second amino acid that can be broken is tyrosine, but this amino acid is placed in the C terminal spot, therefore will not be involved in the hydrolysis.

3 0

2 years ago

How many molecules are there in 345 grams of carbon dioxide?

Mekhanik [1.2K]

You take the grams of CO₂ times Avogadro's number divided by the molar mass.

6 0

2 years ago

Read 2 more answers

If 20.0 grams of Al is placed into a solution containg

meriva

Answer:

m H2(g) = 2.241 g H2(g)

Explanation:

2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g)

limit reagent:

∴ Mw Al = 26.982 g/mol

∴ Mw H2SO4 = 98.0785 g/mol

⇒ n Al = (20 g Al)×(mol/26.982 g) = 0.7412 mol Al

⇒ n H2SO4 = ( 115 g H2SO4 )×(mol/98.0785 g) = 1.173 mol H2SO4

⇒ n H2 = (0.7412 mol Al)×(3 mol H2/ 2 mol Al) = 1.112 mol H2

∴ Mw H2 = 2.016 g/mol

⇒ g H2 = (1.112 mol H2)×(2.016 g/mol) = 2.241 g H2

5 0

2 years ago