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yawa3891 [41]
2 years ago
7

What is a water cycle​

Chemistry
2 answers:
Rina8888 [55]2 years ago
5 0

Answer:

it shows the continuous movement of water within the earth and atmosphere

marissa [1.9K]2 years ago
4 0

Answer:

the cycle of water and how it evaporates with energy from the sun and the droplets are stored in clouds which is condensation and when it rains or snows those are forms of precipitation

Explanation:

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Work is performed on an object by raising it 2 m above the floor. Which of the
devlian [24]

Answer: Id say C

Explanation:

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3 years ago
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When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Natasha2012 [34]

When carbon reacts with oxygen it forms CO2. This can depicted by the below equation.

C + O2→ CO2

It has been mentioned that when 14.4 g of C reacts with 53.9 g of O2, then 15.5 g of O2 remains unreacted. <u>This indicates that Carbon is the limiting reagent and hence the amount of CO2 produced is based on the amount of Carbon burnt.</u>

C + O2→ CO2

In the above equation , 1 mole of carbon reacts with 1 mole of O2 to produce 1 mole of CO2.

In this case 14.4 g of Carbon reacts with 53.9 of O2 to produce "x"g of CO2.

<u>No of moles = mass of the substance÷molar mass of the substance</u>

No of moles of carbon = 14.4 /12= 1.2 moles

No of moles of O2 = Mass of reacted O2/Molar mass of O2.

No of moles of O2 = (Total mass of O2 burned - Mass of unreacted O2)/32

No of moles of O2 = (53.9-15.5) ÷ 32 = 1.2 moles.

Hence as already discussed 1 mole of Carbon reacts with 1 mole of O2 to produce 1 mole of CO2. In this case 1.2 moles of carbon reacts with 1.2 moles of O2 to produce 1.2 moles of CO2.

Moles of carbon dioxide = Mass of CO2 produced /Molar mass of CO2

Mass of CO2 produced(x) = Moles of CO2 ×Molar mass of CO2

Mass of CO2 produced(x) = 1.2 x 44 = 52.8 g

<u>Thus 52.8 g of CO2 is produced.</u>

5 0
2 years ago
2. What is the volume of 40.0 g of N2 at STP?
vampirchik [111]

Answer:

Molar mass of

N

2

=

28 g/mol

Moles of

40.5 g N

2

gas

=

40.5 g

28 g/mol

=

1.45 mol

1 mol

of any gas at

STP

occupies

22.4 L

of volume.

1.45 mol

of

N

2

gas will occupy

1.45

mol

×

22.4 L

1

mol

=

32.48 L

3 0
2 years ago
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