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Artyom0805 [142]
3 years ago
5

One gallon of pure isooctane is about 230 moles. How many moles of O2 would be required to completely combust one gallon of isoo

ctane?
Chemistry
1 answer:
poizon [28]3 years ago
3 0

Answer:

Explanation:

Hello,

At first, consider the balanced reaction for the combustion of the isooctane:

C_8H_{18}+\frac{25}{2} O_2-->8CO_2+9H_2O

Now, the stoichiometric relationship between the hydrocarbon and the oxygen leads to:

molO_2=230molC_8H_{18}(\frac{\frac{25}{2}mol O_2 }{1mol C_8H_{18}} )=2875molO_2

Best regards.

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Answer:

Explanation:

a )

m = m₀ e^{-\lambda t

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λ = .693 / half life

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b )

m = 50 x e^{-.0004358\times 500}

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c )

40 = 50 e^{-.0004358t

.8 = e^{-.0004358t

e^{.0004358t = 1.25

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t = 512 years .

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Nitric monoxide (NO) reacts with oxygen gas to form nitrogen dioxide (NO₂), a dark brown gas. If 5.895 mol of NO is mixed with 2
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Step2: Determine the grams of NO2:

?g NO2 = moles O2 x (2moles NO2/1 mol O2) x (MM NO2/ 1 mol NO2) = 2.503 x 2 x 46 = 230.276 g NO2

Step 3: Determine the amount of excess reagent unreacted

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moles NO unreacted = total moles NO - moles NO reacted = 5.895-5.006 =0.889 moles NO unreacted

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Explanation:

The given following standard cell notation.  

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