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3 years ago

8. The density of an iron nail is the same as the density of an iron frying pan. Explain

1 answer:

6 0

A pure iron frying pan will have the same density as a pure iron anything under the same conditions, however pure iron is rarely used to make things. As their is carbon and traces of various metals, so the density will typically be slightly different, you can lower the density of the item with slightly higher density by heating it but leaving the lower density item cooler. Density is property of material that is independent of shape, volume, size and mass.

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total kinetic energy of all the atoms that make up a sample of matter, would that be heat or mechanical????

Yuki888 [10]

Generally speaking mechanical energy is energy which physically moves (the object), while the thermal energy is energy from the movement of atoms.
Basically temperature is a measurement of atomic movement (doesn't move object as a whole).
Hence heat.

7 0

3 years ago

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zhenek [66]

Answer:

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Explanation:

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3 years ago

In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H2O (g) ⇌

Oksana_A [137]

Answer: Equilibrium constant is 0.70.

Explanation:

Initial moles of $CO$ = 0.35 mole

Volume of container = 1 L

Initial concentration of $CO=\frac{moles}{volume}=\frac{0.35moles}{1L}=0.35M$

Initial moles of $H_2O$ = 0.40 mole

Volume of container = 1 L

Initial concentration of $H_2O=\frac{moles}{volume}=\frac{0.40moles}{1L}=0.40M$

equilibrium concentration of $CO=\frac{moles}{volume}=\frac{0.18moles}{1L}=0.18M$ [/tex]

The given balanced equilibrium reaction is,

$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

Initial conc. 0.35 M 0.40M 0 0

At eqm. conc. (0.35-x) M (0.40-x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CO_2]\times [H_2O]}{[CO]\times [H_2O]}$

$K_c=\frac{x\times x}{(0.40-x)(0.35-x)}$

we are given : (0.35-x)= 0.18

x = 0.17

Now put all the given values in this expression, we get :

$K_c=\frac{0.17\times 0.17}{(0.40-0.17)(0.35-0.17)}$

$K_c=0.70$

Thus the value of the equilibrium constant is 0.70.

5 0

3 years ago

What pressure in atmospheres(atm) is equal to 45.6 kPa?

postnew [5]

1 kpa = 0.0098692327 atm so just multiply that by 45.6

4 0

4 years ago

Si una masa dada de hidrógeno ocupa 40 litros a 700 grados torr. ¿Qué volumen ocupará a 1 atmósfera de presión? (dar la presión

Svetach [21]

Answer:

$V_2=36.84L$

Explanation:

Hola,

En este caso, podemos usar la ley de Boyle, la cual nos permite analizar el comportamiento volumen-presión en un gas ideal de manera inversamente propocional:

$P_1V_1=P_2V_2$

Así, dado el volumen y la presión inicial, la cual se convierte a atmósferas (760 torr = 1atm), calculamos el volumen final a 1 atm como se muestra a continuación:

$V_2=\frac{P_1V_1}{P_2}=\frac{700torr*\frac{1atm}{760torr}*40l }{1atm}\\ \\V_2=36.84L$

Saludos!

7 0

3 years ago

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