Question

1. The emission spectrum of mercury atoms has a bright green line with wavelength

Answer 1

Emission spectrum results from the movement of an electron from a higher to a lower energy level. The frequency of the photon is 5.5 * 10^14 Hz.

From the formula;

E = hc/λ

h = Plank's constant =$6.6 * 10^-34$ Js

c = speed of light=  $3 * 10^8$

λ = wavelength = $546.1 * 10^-9$ m

E =  $6.6 * 10^-34 * 3 * 10^8/546.1 * 10^-9$

E =$3.63 * 10^-19$ J

Also;

E =hf

Where;

h = Planks's constant

f = frequency of photon

f = E/h

f = $3.63 * 10^-19 J/6.6 * 10^-34$

f = $5.5 * 10^14$ Hz

Learn more: brainly.com/question/18415575