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Georgia [21]
2 years ago
10

1. The emission spectrum of mercury atoms has a bright green line with wavelength

Chemistry
1 answer:
SashulF [63]2 years ago
5 0

Emission spectrum results from the movement of an electron from a higher to a lower energy level. The frequency of the photon is 5.5 * 10^14 Hz.

From the formula;

E = hc/λ

h = Plank's constant =6.6 * 10^-34 Js

c = speed of light=  3 * 10^8

λ = wavelength = 546.1 * 10^-9 m

E =  6.6 * 10^-34 * 3 * 10^8/546.1 * 10^-9

E =3.63 * 10^-19 J

Also;

E =hf

Where;

h = Planks's constant

f = frequency of photon

f = E/h

f = 3.63 * 10^-19 J/6.6 * 10^-34

f = 5.5 * 10^14 Hz

Learn more: brainly.com/question/18415575

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Since, we know the avagadro number is 6.02 x 10²³, we only have two unknown values left which are the molecular mass of CH3OH and its mole.

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Number of moles of CH3OH = (9.79 x 10^24)/6.02 x 10²³) =  16.263 moles.

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</span>
Mass in grams = 16.263 x 32 = 520g






6 0
3 years ago
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