1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Georgia [21]
2 years ago
10

1. The emission spectrum of mercury atoms has a bright green line with wavelength

Chemistry
1 answer:
SashulF [63]2 years ago
5 0

Emission spectrum results from the movement of an electron from a higher to a lower energy level. The frequency of the photon is 5.5 * 10^14 Hz.

From the formula;

E = hc/λ

h = Plank's constant =6.6 * 10^-34 Js

c = speed of light=  3 * 10^8

λ = wavelength = 546.1 * 10^-9 m

E =  6.6 * 10^-34 * 3 * 10^8/546.1 * 10^-9

E =3.63 * 10^-19 J

Also;

E =hf

Where;

h = Planks's constant

f = frequency of photon

f = E/h

f = 3.63 * 10^-19 J/6.6 * 10^-34

f = 5.5 * 10^14 Hz

Learn more: brainly.com/question/18415575

You might be interested in
PLEASE HELP!!
Neporo4naja [7]
Fermentation
got it right on the test :)
7 0
2 years ago
What is the volume of 0.640 grams of Oz gas at Standard Temperature and Pressure (STP)?
Ilia_Sergeevich [38]

Answer: The volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

Explanation:

Given: Mass of O_{2} gas = 0.640 g

Pressure = 1.0 atm

Temperature = 273 K

As number of moles is the mass of substance divided by its molar mass.

So, moles of O_{2} (molar mass = 32.0 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.640 g}{32.0 g/mol}\\= 0.02 mol

Now, ideal gas equation is used to calculate the volume as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\1.0 atm \times V = 0.02 mol \times 0.0821 L atm/mol K \times 273 K\\V = 0.449 L

Thus, we can conclude that the volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

6 0
3 years ago
Match the scientists to their contributions to the development of the periodic table.
stiv31 [10]
Where’s the chart and scientists?
3 0
3 years ago
5.36 liters of nitrogen gas are at STP. What would be the new volume if we increased the moles from 3.5 moles to 6.0 moles?
Aleksandr [31]

Answer:

V_2=9.20L

Explanation:

Hello there!

In this case, according to the given STP (standard pressure and temperature), it is possible for us to realize that the equation to use here is the Avogadro's law as a directly proportional relationship between moles and volume:

\frac{V_2}{n_2}= \frac{V_1}{n_1}

In such a way, given the initial volume and both initial and final moles, we can easily compute the final volume as shown below:

V_2= \frac{V_1n_2}{n_1} \\\\V_2=\frac{5.36L*6.0mol}{3.5mol}\\\\V_2=9.20L

Best regards!

3 0
3 years ago
How many atoms is 2.34 moles of titanium?
BartSMP [9]
2.34 moles titanium x (6.022 x 10^23)/1 mole titanium = 1.41 x 10^24
7 0
2 years ago
Read 2 more answers
Other questions:
  • The word hydrolysis has two roots, hydro and lysis. describe how this term relates to the chemical reaction illustrated in model
    7·1 answer
  • What does it mean for an element to be oxidized?
    7·1 answer
  • 30) How many grams of CH3OH must be added to water to prepare 210 mL of a solution that is
    15·1 answer
  • Why Chlorine gas used in ww1
    9·1 answer
  • Why do scientists look for patterns in the world?
    10·1 answer
  • Which two reactions are opposites of each<br> other?
    12·2 answers
  • Once formed, how many valence electrons does an anion hold?
    7·1 answer
  • How many times are you testing your prototype? Question 3 options: <br> 10 3 0
    13·1 answer
  • How can magnetic force be exerted on objects?
    5·1 answer
  • When a stone is dipped in a glass containing some water, the level of water rises but when a
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!