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klio [65]
2 years ago
12

Question 3 of 25

Chemistry
1 answer:
Colt1911 [192]2 years ago
8 0

The statement that describes a question that can guide the design of a scientific investigation could be about the necessity of a controlled variable. The correct answer is A.

<h3>What is a controlled variable?</h3>

It is a variable whose values are controlled by the researcher during the course of experimental investigations.

When designing an experiment, it is necessary to identify the different variables that would be involved for a successful investigation.

Variables can be independent, dependent, controlled, or constant. Identifying the necessary variables will help in designing the experiment.

More on variables can be found here: brainly.com/question/15740935

#SPJ1

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Differentiate between satured and unsatured fats
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What were the units of light energy emitted by blackbody radiation originally called?
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Please help me ASAP I’ll mark Brainly
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5 0
3 years ago
9. Thallium-208 has a half-life of 3.053 min. How long will it take for 120 g of it to decay
damaskus [11]

Answer:

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

Explanation:

Radioactive isotopes decay exponentially in time, the mass of the isotope (m(t)), in grams, is described by the formula in time (t), in minutes:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

m_{o} - Initial mass of the isotope, in grams.

\tau - Time constant, in minutes.

In addition, the time constant associated with the isotope decay can be described in terms of half-life (t_{1/2}), in minutes:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m(t) = 7.5\,g, m_{o} = 120\,g and t_{1/2} = 3.053\,min, then the time taken by the isotope is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{3.053\,min}{\ln 2}

\tau \approx 4.405\,min

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(4.405\,min)\cdot \ln \left(\frac{7.5\,g}{120\,g} \right)

t \approx 12.213\,min

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

4 0
3 years ago
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