Complete Question:
When specially prepared Hydrogen atoms with their electrons in the 6f state are placed into a strong uniform magnetic field, the degenerate energy levels split into several levels. This is the so called normal Zeeman effect.
Ignoring the electron spin what is the largest possible energy difference, if the magnetic field is 2.02 Tesla?
Answer:
ΔE = 1.224 * 10⁻²² J
Explanation:
In the 6f state, the orbital quantum number, L = 3
The magnetic quantum number,
The change in energy due to Zeeman effect is given by:
Magnetic field B = 2.02 T
Bohr magnetron,
ΔE = 1.224 * 10⁻²² J
Answer:
A) 0.50 mV
Explanation:
In this problem, we can think the wings of the bird as a metal rod moving across a magnetic field. So, and emf will be induced into the wings of the bird, according to the formula:
where
is the strength of the magnetic field
v = 13 m/s is the speed of the bird
L = 1.2 m is the wingspan of the bird
is the angle between the direction of motion and the direction of the magnetic field
Substituting numbers into the formula, we find
Voltage, resistance and current are the three components that must be present for a circuit to exist. A circuit will not be able to function without these three components. Voltage is the main electrical source that is present in a circuit. :)
The appropriate response is the negative charge owing fascination of positive charge of the plastic street. Particles are comprised of protons, neutrons, and electrons. Neutrons are unbiased and don't have any charge whatsoever. Protons convey a positive charge, and electrons convey the negative charge. At the point when a question has a positive charge, it has a bigger number of protons than electrons.
Answer:
the time required for the sound to travel between the whales 0.66 S.
Explanation:
As given in the problem, the velocity of sound wave () is governed by the equation
Given, and
So for salt water, the velocity of sound wave () can be written as
As the whales are d = 1 Km or 1000 m apart from each other, so the time () required for the sound wave to travel this distance is given by