Answer:
a) 16.46 seconds.
b) 13.46 seconds
c) 2.67 m/s²
Explanation:
Acceleration = a = 1.35 m/s²
Final velocity = v = 80 km/h =
Initial velocity = u = 0
Equation of motion
Time taken to accelerate to top speed is 16.46 seconds.
Acceleration = a = -1.65 m/s²
Initial velocity = u = 80 km/h=
Final velocity = v = 0
Time taken to stop the train from top speed is 13.46 seconds
Initial velocity = u = 80 km/h=
Time taken = t = 8.3 s
Final velocity = v = 0
Emergency deceleration is 2.67 m/s²
Answer:
a. Picture attached
b. V, X
c.
d. It makes sense cosidering that a normal heart beat rate is between 60 and 100 beats per minute (bpm).
Explanation:
First we have to identify the unknown of this problem:
Considering the characteristics of the problem and that distance and velocity are specified, the acceleration is constant, for that reason we use the equations of uniformly accelerated motion as follows:
If we reorganize the equations, considering that and
are zero because motion starts from rest , we have:
Finally, the analysis of the result leaves us to understand why the normal heart beat rate varies between 60 and 100 bpm.
