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slava [35]
1 year ago
12

A single-phase, 125-volt receptacle installed to serve a washing machine in the laundry room of a dwelling unit must be installe

d within at least ______ of the intended location of the appliance.
Physics
1 answer:
Allisa [31]1 year ago
8 0

A single-phase, 125-volt receptacle installed to serve a washing machine in the laundry room of a dwelling unit must be installed within at least 6 Feet of the intended location of the appliance.

In  every kitchen, dining room, library, bedroom or area of dwelling units etc the receptacle units outlet shall be installed with provision specified in article 210.52(A)(1) and through (A)(4) while learning the article attached

Spacing: Receptacles should be installed at the point that wall space is more than 6ft or 1.8m from the receptacle.

Read more about Dwelling unit:

brainly.com/question/28283274

#SPJ4

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A force of constant magnitude pushes a box up a vertical surface, as shown in the figure.
Ray Of Light [21]

The work done on the box by the applied force is zero.

The work done by the force of gravity is 75.95 J

The work done on the box by the normal force is 75.95 J.

<h3>The given parameters:</h3>
  • Mass of the box, m = 3.1 kg
  • Distance moved by the box, d = 2.5 m
  • Coefficient of friction, = 0.35
  • Inclination of the force, θ = 30⁰

<h3>What is work - done?</h3>
  • Work is said to be done when the applied force moves an object to a certain distance

The work done on the box by the applied force is calculated as;

W = Fd cos(\theta)\\\\W = (ma)d \times cos(\theta)

where;

a is the acceleration of the box

The acceleration of the box is zero since the box moved at a constant speed.

W = (0) d \times cos(30)\\\\W = 0 \ J

The work done by the force of gravity is calculated as follows;

W = mg \times d\\\\W = 3.1 \times 9.8 \times 2.5 \\\\W = 75.95 \ J

The work done on the box by the normal force is calculated as follows;

W = (F_n) \times d\\\\W = (mg + F sin\theta) \times d\\\\W = (mg + 0) \times d\\\\W = mgd\\\\W = 3.1 \times 9.8 \times 2.5\\\\W = 75.95 \ J

Learn more about work done here: brainly.com/question/8119756

8 0
2 years ago
Friction, conduction and induction are three ways of creating a static charge on an object. Which method or methods will produce
Agata [3.3K]
Friction as it will move charge (electrons) from one object to another
5 0
3 years ago
D.) How can you demonstrate the magnetic force? Write with an example
Lena [83]

Explanation:

d) Magnetic force is the power that pulls materials together (magnet e. g iron)

an example :how magnet can pick up a coin.

e) frictional force produces when two surfaces are in contact with each other.

effects of friction : I) it produces heat

II) it causes loss in power.

4 0
3 years ago
A 2.8 kg grinding wheel is in the form of a solid cylinder of radius 0.1 m. a) What constant torque will bring it from rest to a
kogti [31]

Answer:

a) τ =  0.672 N m , b) θ = 150 rad , c) W = 100.8 J

Explanation:

a) for this part let's start by finding angular acceleration, when the angular velocity stops it is zero (w = 0)

       w = w₀ + α t

       α = -w₀ / t

       α = 120 / 2.5

       α = 48 rad / s²

The moment of inertia of a cylinder is

       I = ½ M R²

Let's calculate the torque

      τ = I α

      τ = ½ M R² α

      τ = ½ 2.8 0.1² 48

      τ =  0.672 N m

b) we look for the angle by kinematics

      θ = w₀ t + ½ α t2

      θ = ½ α t²

      θ = ½ 48 2.5²

      θ = 150 rad

c) work in angular movement

      W = τ θ

      W = 0.672 150

      W = 100.8 J

7 0
3 years ago
What percentage of energy can be transformed when an energy transformation from potential to kinetic occurs?
GREYUIT [131]

Answer:

100%

Explanation:

i did the same question

7 0
3 years ago
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