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slava [35]
1 year ago
12

A single-phase, 125-volt receptacle installed to serve a washing machine in the laundry room of a dwelling unit must be installe

d within at least ______ of the intended location of the appliance.
Physics
1 answer:
Allisa [31]1 year ago
8 0

A single-phase, 125-volt receptacle installed to serve a washing machine in the laundry room of a dwelling unit must be installed within at least 6 Feet of the intended location of the appliance.

In  every kitchen, dining room, library, bedroom or area of dwelling units etc the receptacle units outlet shall be installed with provision specified in article 210.52(A)(1) and through (A)(4) while learning the article attached

Spacing: Receptacles should be installed at the point that wall space is more than 6ft or 1.8m from the receptacle.

Read more about Dwelling unit:

brainly.com/question/28283274

#SPJ4

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A rock is thrown downward from an unknown height above the ground with an initial speed of 6.1 m/s. It strikes the ground 1.7 s
insens350 [35]

Answer:

24.531 m

Explanation:

t = Time taken = 1.7 s

u = Initial velocity = 6.1 m/s

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

Equation of motion

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=6.1\times 1.7+\dfrac{1}{2}\times 9.8\times 1.7^2\\\Rightarrow s=24.531\ m

The initial height of the rock above the ground is 24.531 m

7 0
3 years ago
USATESTPREP
natulia [17]

Answer:

C, D, and E

Explanation:

5 0
2 years ago
A hydraulic lift raises 1140 kg car through a height of 2.4 m. What is the potential energy
Sladkaya [172]
1140x9.8x2.4= 26,812.8 significant figures Make it 27,000
5 0
2 years ago
Calculate the force which will produce an extension of 0.30mm in a steel wire with a length of 4.0m and a cross section area of
Anna [14]

Given data:

* The extension of the steel wire is 0.3 mm.

* The length of the wire is 4 m.

* The area of cross section of wire is,

A=2\times10^{-6}m^2

* The young modulus of the steel is,

Y=2.1\times10^{11}\text{ Pa}

Solution:

The young modulus of the steel in terms of the force and extension is,

Y=\frac{F\times l}{A\times dl}

where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,

Substituting the known values,

\begin{gathered} 2.1\times10^{11}=\frac{F\times4}{2\times10^{-6}\times0.3\times10^{-3}} \\ F=0.315\times10^2\text{ N} \\ F=31.5\text{ N} \end{gathered}

Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.

7 0
1 year ago
How do you calculate speed
Kryger [21]

Answer:

distance(d)=.....

time(t)=....

speed =?

we know that

speed =distance /time

8 0
3 years ago
Read 2 more answers
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