Consider the following pulley system. A block of mass m is connected to a translational spring of stiffness k through a cable, w
hich passes by a pulley. The pulley rotates about a fixed mass center 0. The moment of inertia of the pulley about its mass center is I_0. Determine the equation of motion using the energy method.
1 answer:
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Answer:
2165800 Pa
Explanation:
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Answer:
2074.2 KW
Explanation:
<u>Determine power developed at steady state </u>
First step : Determine mass flow rate ( m )
m / Mmax = ( AV )₁ P₁ / RT₁ -------------------- ( 1 )
<em> where : ( AV )₁ = 8.2 kg/s, P₁ = 0.35 * 10^6 N/m^2, R = 8.314 N.M / kmol , </em>
<em> T₁ = 720 K . </em>
insert values into equation 1
m = 0.1871 kmol/s ( mix )
Next : calculate power developed at steady state ( using ideal gas tables to get the h values of the gases )
W( power developed at steady state )
W = m [ Yco2 ( h1 - h2 )co2
Attached below is the remaining part of the detailed solution
Answer:
Explanation:
Given data:
Diffusion constant for nitrogen is
Diffusion flux
concentration of nitrogen at high presuure = 2 kg/m^3
location on which nitrogen concentration is 0.5 kg/m^3 ......?
from fick's first law
Take C_A as point on which nitrogen concentration is 2 kg/m^3
Assume X_A is zero at the surface