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Leona [35]
3 years ago
14

Technician A says that squeeze-type resistance spot welding (STRSW) may be used on open butt joints. Technician B says that repl

acement spot welds may be made adjacent to the original spot weld locations. Who is right
Engineering
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

B only

Explanation:

Squeeze-type resistance spot welding (STRSW)is a type of electric resistance welding that brings about the weld on interfacing sheet metal pieces through which heat generated from electric resistance bring about fusion and welding of the two pieces together

Therefore, it is not meant for opening but joints but it can be used for making replacement spot welds adjacent to the original spot weld due to the smaller heat affected zone (HAZ) created by the STRSW process.

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A concrete mix design calls for 6.5 sacks of cement, a water/cement ratio of 0.45, and an air content of 2.5%. 1. Complete the m
RUDIKE [14]

Answer:

28.6 kg

Explanation:

The final weight can be calculated from the mixing data and formulae which is given as follows:

cement content = \frac{water content}{water - cement ratio}

Computing the parameters and checking the tables gives 28.6 kg.

7 0
3 years ago
Read 2 more answers
Tech A says that horsepower is a measurement simply of the amount of work being performed. Tech B says that horsepower can be ca
snow_tiger [21]

Answer:

Tech B

Explanation:

Horsepower (hp) refers to a unit of measurement of power in respect of the output of engines or motors.

Horsepower is the common unit of power. It indicates the rate at which work is done.

The formula \frac{rpm*T}{5252}, where rpm is the engine speed, T is the torque, and 5,252 is radians per second.

So,

Tech B is correct

6 0
2 years ago
I need help on the Coderz Challenge missions 3 part 3. PLEASE HELP!
allsm [11]

Answer:

the answer how you analyzs the problwm

6 0
3 years ago
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If a generator has 120 volts and 22 amps, how many ohms are needed so the generator will not explode.
daser333 [38]
120 volt divided by 22 ampere
= 5.4545454545455 ohm (Ω)
P = V × I
= 120 volt × 22 ampere
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7 0
2 years ago
Two different fuels are being considered for a 2.5 MW (net output) heat engine which can operate between the highest temperature
sveta [45]

Answer:

If the heat engine operates for one hour:

a) the fuel cost at Carnot efficiency for fuel 1 is $409.09 while fuel 2 is $421.88.

b) the fuel cost at 40% of Carnot efficiency for fuel 1 is $1022.73 while fuel 2 is $1054.68.

In both cases the total cost of using fuel 1 is minor, therefore it is recommended to use this fuel over fuel 2. The final observation is that fuel 1 is cheaper.

Explanation:

The Carnot efficiency is obtained as:

\epsilon_{car}=1-\frac{T_c}{T_H}

Where T_c is the atmospheric temperature and T_H is the maximum burn temperature.

For the case (B), the efficiency we will use is:

\epsilon_{b}=0.4\epsilon_{car}

The work done by the engine can be calculated as:

W=\epsilon Q=\epsilon H_v\cdot m_{fuel} where Hv is the heat value.

If the average net power of the engine is work over time, considering a net power of 2.5MW for 1 hour (3600s), we can calculate the mass of fuel used in each case.

m=\frac{P\cdot t}{\epsilon H_v}

If we want to calculate the total fuel cost, we only have to multiply the fuel mass with the cost per kilogram.

TC=m\cdot c

8 0
2 years ago
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