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Zielflug [23.3K]

2 years ago

15

The ability to clearly see objects at a distance but not close up is properly called ________. The ability to clearly see object

s at a distance but not close up is properly called ________.

1 answer:

melamori03 [73]2 years ago

5 0

Answer:

Hyperopia

Explanation:

In hyperopia ,people face difficulties to see close up object , but can see object easily which are at a distance.

The main reason of hyperopia is our eyeball.When our eyeball become too short , then light focus behind the retina. Sowe will face problem to see near object but we can see distance object easily. Hyperopia is the opposite of nearsightedness. Hyperopia can be corrected by using contact lenses.

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Assume that a lightning bolt can be modeled as a long, straight line of current. If 16 C of charge passes by a point in 1.50 x 1

Reptile [31]

Answer:

$B = 7.9012*10^{-5}T$

Explanation:

To solve the problem, the concepts related to the magnetic field and the current produced in a lightning bolt are necessary.

The current is defined by the load due to time, that is to say

$I= \frac{q}{t}$

Where,

$q= Charge$

$t = time$

So the current can be expressed as:

$I = \frac{16}{1.5*10^{-3}}$

$I = 10666.67A$

Once the current is found it is now possible to find the magnetic field, as this is given by the equation,

$B =\frac{\mu_0}{2\pi}\frac{I}{r}$

Where,

$\mu_0 =$ Permeability Constant

I= Current

r= radius

Replacing the values we have

$B=\frac{4\pi*10^{-7}}{2\pi}(\frac{10666.67}{27})$

$B = 7.9012*10^{-5}T$

7 0

3 years ago

Setler [38]

I think the answer is B.

Hope this helps.

5 0

3 years ago

Read 2 more answers

You are in charge of designing a movie stunt for a new Fast and Furious film. In this scene a stunt person has to jump from a br

blondinia [14]

Answer:

103.5 meters

Explanation:

Given that a stunt person has to jump from a bridge and land on a boat in the water 22.5 m below. The boat is cruising at a constant velocity of 48.3 m/s towards the bridge. The stunt person will jump up at 6.45 m/s as they leave the bridge.

The time the person will jump to a certain spot under the bridge can be calculated by using the formula below:

h = Ut + 1/2gt^2

since the person will fall under gravity, g = 9.8 m/s^2

Also, let assume that the person jump from rest, then, U = 0

Substitute h, U and g into the formula above

22.5 = 1/2 * 9.8 * t^2

22.5 = 4.9t^2

22.5 = 4.9t^2

t^2 = 22.5/4.9

t^2 = 4.59

t = $\sqrt{4.592}$

t = 2.143 seconds

From definition of speed,

speed = distance /time

Given that the boat is cruising at a constant velocity of 48.3 m/s towards the bridge, substitute the speed and the time to get the distance.

48.3 = distance / 2.143

distance = 48.3 * 2.143

distance = 103.5 m

Therefore, the boat should be 103.5m away from the bridge at the moment the stunt person jumps?

3 0

3 years ago

One mole of an ideal gas does 3000 J of work on its surroundings as it expands isothermally to a final pressure of 1.00 atm and

taurus [48]

Answer:

(a) Initial volume will be 7.62 L

(b) Final temperature will be 303.85 K

Explanation:

We have given one mole of ideal gas done 3000 J

So work done W = 3000 J

Let initial volume is $V_1$ and initial pressure $P_1=1atm$ ( As pressure is constant )

Final volume $V_2=25L$ = 0.025 $m^3$

Number of moles n = 1

(B) From ideal gas of equation we know that $PV=nRT$

So $1.01\times 10^5\times0.025=1\times 8.31\times T$

T = 303.85 Kelvin

(B) For isothermal process work done is equal to

$W=nRTln\frac{V_2}{V_1}$

$3000=1\times 8.314\times 303.85\times ln\frac{0.025}{V_1}$

$ln\frac{0.025}{V_1}=1.1881$

$\frac{0.025}{V_1}=3.2808$

$V_2=0.00846m^3=7.62L$

So initial volume will be 7.62 L

5 0

3 years ago

What is the final velocity, in meters per second, of a freight train that accelerates at a rate of 0.085 m/s2 for 7.5 min, start

Llana [10]

Answer:

$v_f=41.65\frac{m}{s}$

Explanation:

The final velocity is given by the following kinematic equation:

$v_f=v_0+at$

Here, $v_0$ is the initial velocity, a is the body's acceleration and t is the motion time. We have to convert the time to seconds:

$7.5min*\frac{60s}{1min}=450s$

Now, we calculate the final velocity:

$v_f=3.4\frac{m}{s}+(0.085\frac{m}{s^2}(450s))\\v_f=41.65\frac{m}{s}$

4 0

3 years ago