Answer: Objective Observations
Explanation: The first step in the Scientific Method is to make objective observations. These observations are based on specific events that have already happened and can be verified by others as true or false
Answer:
0.249
Explanation:
Perihelion = 4.43 x 10^9 km
Aphelion = 7.37 x 10^9 km
Let e be the eccentricity and a be the length of semi major axis.
The relation between the semi major axis, perihelion and aphelion s given by
Semi major axis = half of sum of perihelion and aphelion

a = 5.9 x 10^9 km
The relation between the perihelion, semi major axis and the eccentricity is given by
Perihelion = a (1 - e)
4.43 x 10^9 = 5.9 x 10^9 (1 - e)
0.751 = 1 - e
e = 0.249
The potential energy of the monkey at the given position is 600.9 J.
<h3>What is potential energy?</h3>
Potential energy is the energy stored in a body that depends upon the relative position of various parts of the body.
It increases with increase in the height of the object above the ground level.
<h3>
Potential energy of the monkey</h3>
The potential energy of the monkey is calculated as follows;
P.E = mgh
P.E = mg (L sin43)
where;
- m is mass of the monkey, given as 16.9 kg
- g is acceleration due to gravity, given as 9.8 m/s²
- L is length of the vine given as 5.32 m
Substitute the given parameters and solve potential energy of the monkey
P.E = (16.9)(9.8)( 5.32 x sin 43)
P.E = 600.9 J
Thus, the potential energy of the monkey at the given position is 600.9 J.
Learn more about potential energy here: brainly.com/question/1242059
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Answer: D (Chloroplasts)
Explanation: The chloroplast goes through a process called photosynthesis. During this process, specialized pigments in the chloroplast absorb sunlight and use this energy to combine carbon dioxide and water to make glucose and oxygen.
Initial velocity u = 20 m/s
Initial horizontal velocity = 20 cos30° = 20 * 0.866 = 17.32 m/sec.
Initial vertical velocity = 20 sin30° = 20 * 1/2 = 10 m/sec.
time taken t = u/g = 10/10 =1 sec. ( approximating g to 10m/sec^2)
Maximum height h = ut + 1/2 * g * t^2
h = 10 *1 - 1/2 * 10 * 1* 1
h = 10 - 5 = 5 metres.
Total time in air = 2t = 2 seconds.