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Contact [7]
3 years ago
7

How do you solve the inequality to -3|2-4u|+5<-13

Mathematics
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

u=-1

Step-by-step explanation:

-3|2-4u|+5<-13

-6+12u+5<-13

12u<-13-5+6

12u<-12

12u/12<-12/12

u=-1

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Help please need it ASAP correct
Mazyrski [523]

Answer:

p=-7

Step-by-step explanation:

This is how you find it

1) Substitute the p into the equation to get 7(-7)-7=-56. Then you get -49-7=-56. This is true  

Hope this helps! :)

7 0
3 years ago
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Which of the following quartic functions has x= -1 and x = -3 as its only two real zeros
Komok [63]

Answer:

f(x) = x² + 4x + 3

Step-by-step explanation:

Here in this problem, we have to find the quadratic function that has x = - 1 and x = - 3 as the only two real zeros.

So, from the above condition, we can say that (x + 1) and (x + 3) are the only two factors of the function.

Therefore, the function will be f(x) = (x + 1)(x + 3), such that if the function is zero, then the solutions will be x = - 1 and x = - 3.

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7 0
3 years ago
Mathhhhhhhhhhhhhhhhhh
Mice21 [21]
We need to find the points that are solutions, that is, the points that lie in the shaded region.

Let's try the ordered pair (1,2). This isn't in the shaded region, so it is not a solution of the system.

The same goes for (-10, 10) and (-2,0).

But when you plot (0,10), it does lie in the shaded region, so it's a solution of the system of inequalities. 
6 0
4 years ago
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Given segment AC and point B that lies on AC,
ololo11 [35]

The total length of the segment AC is the sum of AB and CB, which gives, CB = 9

<h3>How can the length of CB be found?</h3>

The given parameters are;

  • AC = 17
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  • CB = 57 + 6•x

Required: <em>CB</em>

Solution:

AC = <em>AB + CB</em> by segment addition property

Therefore;

AC = 17 = 32 + 3•x + 57 + 6•x = 89 + 9•x

17 = 89 + 9•x

x =  \frac{17 - 89}{9}  =  - 8

CB = 57 + 6•x = 57 + 6 × (-8) = 9

Therefore;

  • <u>CB = 9</u>

Learn more about segment addition postulate here: brainly.com/question/1721582

#SPJ1

8 0
2 years ago
Is 3 2/3 greater than the square root of 11
Dennis_Churaev [7]

Answer:

Yes

Step-by-step explanation:

3 2/3 ~ 3.667

sqrt11 ~ 3.31662479

4 0
3 years ago
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