If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
Answer: SHE GOT 13 MONTHS YES SHE DO, 13 MONTHS LEFT IS ANSWER
Step-by-step explanation:
<em>Answer:</em>
<h2>
<em>the </em><em>SSS </em><em>similarity</em><em> </em><em>theorem</em></h2>
<em>Please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em>.</em><em>.</em><em>.</em>
<em>Hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>
X in the first equation
because 3x + 6y = 9 can be reduced by dividing by 3, thus, giving u
x + 2y = 3.....x = -2y + 3...which u would sub in for x in the other equation
Answer:
its dont make since bro what is the fraction?
Step-by-step explanation
divide