Answer:
- 278.85 J
Explanation:
Given that:
Pressure = 1.1 atm
The initial volume V₁ = 0.0 L
The final volume V₂ = 2.5 L
The work that takes place in a reaction at constant pressure can be expressed by using the equation:
W = P(V₂ - V₁ )
Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:
W = - P(V₂ - V₁ )
W = -1.1 atm ( 2.5 - 0.0) L
W = -1.1 atm (2.5 L)
W = -2.75 atm L
Recall that:
1 atm L = 101.4 J
Therefore;
-2.75 atm L = ( -2.75 × 101.4 )J
= -278.85 J
Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm = - 278.85 J
Answer:
See below.
Step-by-step explanation:
<em>Method 1:
</em>
You know that oxygen is a <em>non-metal.
</em>
If the compound is ionic, the oxygen must be combined with a <em>metal</em>.
The Mg must be a metal.
<em>Method 2:</em>
In the formulas of ionic compounds, the positive ion (usually a metal) is written first.
Answer:
o thats pretty cool for points its a new moon
The ion has a larger radius compare to that of its neutral form. Let's take for example chlorine. Neutral chlorine has 17 electron. The ion chlorine or Cl- has an addition 1 electron, hence the negative charge. The neutrons in chlorine can not tightly hold all 18 electron as compared to 17 electron.
