<h3><u>Answer and explanation;</u></h3>
Ideal gas law is the mathematical relationship among pressure, volume, temperature, and the number of moles of a gas.
The ideal gas law is given by;
PV=nRT, where
P is the Pressure
V is the volume of the gas.
n is the number of moles
R is the gas constant and
T is the temperature
Answer:
- <u>Tellurium (Te) and iodine (I) are two elements </u><em><u>next to each other that have decreasing atomic masses.</u></em>
Explanation:
The <em>atomic mass</em> of tellurium (Te) is 127.60 g/mol and the atomic mass of iodine (I) is 126.904 g/mol; so, in spite of iodine being to the right of tellurium in the periodic table (because the atomic number of iodine is bigger than the atomic number of tellurium), the atomic mass of iodine is less than the atomic mass of tellurium.
The elements are arranged in increasing order of atomic number in the periodic table.
The atomic number is equal to the number of protons and the mass number is the sum of the protons and neutrons.
The mass number, except for the mass defect, represents the atomic mass of a particular isotope. But the atomic mass of an element is the weighted average of the atomic masses of the different natural isotopes of the element.
Normally, as the atomic number increases, you find that the atomic mass increases, so most of the elements in the periodic table, which as said are arranged in icreasing atomic number order, match with increasing atomic masses. But the relative isotope abundaces of the elements can change that.
It is the case that the most common isotopes of tellurium have atomic masses 128 amu and 130 amu, whilst most common isotopes of iodine have an atomic mass 127 amu. As result, tellurium has an average atomic mass of 127.60 g/mol whilst iodine has an average atomic mass of 126.904 g/mol.
Answer:
The tension in the string is 78.73 N.
Explanation:
The tension in the string can be determined from the expression;
v =
where: v is the speed of the wave in the sting, T is the tension in the string and m is the mass per unit length of the sting.
Given that: v = 16.2 m/s, and m = 0.3 kg/m.
Then;
16.2 =
Square both sides to have,
=
T = x 0.3
= 252.44 x 0.3
= 78.732
T = 78.732 N
The tension in the string is 78.73 N.
Atomic mass of N from periodic table is 14 amu so atomic mass of N₂ will be 2 * 14 = 28 amu
This means that every mole of N₂ has mass equal to 28 g
Answer : The correct option is, (C) 1.1
Solution : Given,
Initial moles of = 1.0 mole
Initial volume of solution = 1.0 L
First we have to calculate the concentration .
The given equilibrium reaction is,
Initially c 0
At equilibrium
The expression of will be,
where,
= degree of dissociation = 40 % = 0.4
Now put all the given values in the above expression, we get:
Therefore, the value of equilibrium constant for this reaction is, 1.1