You have a balloon containing 1 L of air at STP in a vacuum chamber. What will the volume of the balloon be when you reduce the
1 answer:
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Answer:
The coefficient before potassium (K) balances this chemical equation is 2.
Explanation:
_K +Cl₂ → 2KCl
K =1 ; Cl =2
K=1 × 2 = 2
Cl = 1 × 2 = 2
2 K +Cl₂ = 2 KCl
Answer:
Explanation:
Structure of the 2,2,4,4-tetramethyl-3-pentanone is give in the attachment
In 2,2,4,4-tetramethyl-3-pentanone, no alpha hydrogen is present, therefore, enol form is not possible and hence, exist only in keto form.
Explanation for existence of cyclohexa-2,4-diene-1-one only in enol form:
keto form of cyclohexa-2,4-diene-1-one not aromatic and hence less stable.
Whereas enol form it is aromatic which makes it highly stable. that's why cyclohexa-2,4-diene-1-one exists only in enol form.
