The water would be because however much salt you add the water rises
Since the plant is falling, the gravitational energy decreases, so it means b) kinetic energy is increasing.
Hope this helps!! :)
Answer:
0.16Hz
Explanation:
wavelength (λ) = 125 meters
speed (V) = 20 m/s
frequency (F) = ?
Recall that frequency is the number of cycles the wave complete in one
second. And its value depends on the wavelength and speed of the wave.
So, apply the formula V = F λ
Make F the subject formula
F = V / λ
F = 20 m/s / 125 meters
F = 0.16 Hz
The space station completes 2 revolutions each minute, so that it traverses a distance of 2<em>π</em> (100 m) = 200<em>π</em> m each minute, giving it a linear/tangential speed of
<em>v</em> = (200<em>π</em> m) / (60 s) ≈ 10.472 m/s
(a) The astronaut would experience an acceleration of
<em>a</em> = <em>v</em> ² / (100 m) ≈ 1.09662 m/s² ≈ 0.1119<em>g</em> ≈ 0.11<em>g</em>
<em />
(b) Now you want to find the period <em>T</em> such that <em>a</em> = <em>g</em>. This would mean the astronaut has a tangential speed of
<em>v</em> = (200<em>π</em> m) / <em>T</em>
so that her centripetal/radial acceleration would match <em>g</em> :
<em>a</em> = <em>g</em> = ((200<em>π</em> m) / <em>T </em>)² / (100 m)
Solve for <em>T</em> :
(100 m) <em>g</em> = (400<em>π</em> ² m²) / <em>T</em> ²
<em>T</em> ² = (400<em>π</em> ² m²) / ((100 m) <em>g</em>) = (4<em>π</em> ² m)/<em>g</em>
<em>T</em> = √((4<em>π</em> ² m) / (9.8 m/s²)) ≈ 2<em>π</em> √(0.102 s²) ≈ 2.007 s ≈ 2.0 s
