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Harrizon [31]
4 years ago
9

a student conducts an experiment to determine how the additional of salt to water affects the density of the water. the student

fills 3 beakers with equal amounts of water. he then adds 1 cup of salt to the first beaker, 2 cups of salt to the second beaker and no salt to the third beaker. what is the dependent variable in the student's investigation?
Physics
1 answer:
Lera25 [3.4K]4 years ago
3 0
The water would be because however much salt you add the water rises
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Two forces are acting on an object as shown in Fig. on the right. What is the magnitude of the resultant force?
svetlana [45]

Answer:

185 N

Explanation:

Sum of forces in the x direction:

Fₓ = -(80 N cos 75°) + (120 N cos 60°)

Fₓ = 39.3 N

Sum of forces in the y direction:

Fᵧ = (80 N sin 75°) + (120 N sin 60°)

Fᵧ = 181.2 N

The magnitude of the net force is:

F = √(Fₓ² + Fᵧ²)

F = √((39.3 N)² + (181.2 N)²)

F = 185 N

8 0
3 years ago
A flat, circular loop has 18 turns. The radius of the loop is 15.0 cm and the current through the wire is 0.51 A. Determine the
Ostrovityanka [42]

Answer:

The magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.

Explanation:

Given;

number of turns of the flat circular loop, N = 18 turns

radius of the loop, R = 15.0 cm = 0.15 m

current through the wire, I = 0.51 A

The magnetic field through the center of the loop is given by;

B = \frac{N\mu_o I}{2R}

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

B = \frac{N\mu_o I}{2R} \\\\B = \frac{18*4\pi*10^{-7} *0.51}{2*0.15} \\\\B = 3.846 *10^{-5} \ T

Therefore, the magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.

6 0
4 years ago
How long would it take a leopard, running at an average speed of 20 m/s to travel 500 m?
alexandr1967 [171]

Answer:

25 seconds

Explanation:

500/20

4 0
3 years ago
Ammeters should be connected ________ with the circuit being tested.
Viktor [21]
Always should be connected in series! :) 
3 0
4 years ago
Pilots of high-performance fighter planes can be subjected to large centripetal accelerations during high-speed turns. Because o
nika2105 [10]

Answer:

Ratio is 7.58

Explanation:

At the bottom of the circle, the net force is given by

F_{n}=mv^{2}+mg where m is mass of plane, v is the speed of plane, r is vertical circle radius

F_{n}=m(v^{2}+g)

Since W=mg, dividing left side by W and right side by mg we obtain

\frac {F_{n}}{W}= \frac {m(v^{2}+g)}{mg}

\frac {F_{n}}{W}=g(g+\frac {v^{2}}{r})

\frac {F_{n}}{W}=9.81(9.81+\frac {216^{2}}{723})=7.578096

\frac {F_{n}}{W}=7.58

Considering that \frac {F_{n}}{W}=7.58 which is greater than 2, the pilot is advised to wear the anti-G suit

6 0
3 years ago
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