Answer:
185 N
Explanation:
Sum of forces in the x direction:
Fₓ = -(80 N cos 75°) + (120 N cos 60°)
Fₓ = 39.3 N
Sum of forces in the y direction:
Fᵧ = (80 N sin 75°) + (120 N sin 60°)
Fᵧ = 181.2 N
The magnitude of the net force is:
F = √(Fₓ² + Fᵧ²)
F = √((39.3 N)² + (181.2 N)²)
F = 185 N
Answer:
The magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
Explanation:
Given;
number of turns of the flat circular loop, N = 18 turns
radius of the loop, R = 15.0 cm = 0.15 m
current through the wire, I = 0.51 A
The magnetic field through the center of the loop is given by;

Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

Therefore, the magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
Always should be connected in series! :)
Answer:
Ratio is 7.58
Explanation:
At the bottom of the circle, the net force is given by
where m is mass of plane, v is the speed of plane, r is vertical circle radius

Since W=mg, dividing left side by W and right side by mg we obtain


=7.578096
=7.58
Considering that
=7.58 which is greater than 2, the pilot is advised to wear the anti-G suit