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mafiozo [28]
3 years ago
12

A wave with a wavelength of 125 meters is moving at a speed of 20 m/s. What is it’s frequency

Physics
1 answer:
IceJOKER [234]3 years ago
8 0

Answer:

0.16Hz

Explanation:

wavelength (λ) = 125 meters

speed (V) = 20 m/s

frequency (F) = ?

Recall that frequency is the number of cycles the wave complete in one

second. And its value depends on the wavelength and speed of the wave.

So, apply the formula V = F λ

Make F the subject formula

F = V / λ

F = 20 m/s / 125 meters

F = 0.16 Hz

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A company records authors reading their books aloud. These recordings are shared with libraries around the world for people to l
9966 [12]

Answer:

c

Explanation:

the loud noise can reduce the quality of the analog signal

5 0
2 years ago
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A beaker of mass 1.3 kg containing 2.8 kg of water rests on a scale. A 3.7 kg block of a metallic alloy of density 4600 kg/m3 is
Oksana_A [137]

1) Force read on the upper scale: 33.4 N

2) Force read on the lower scale: 43.0 N

Explanation:

1)

The reading on the upper scale is equal to the net force acting on the block of metallic alloy. The net force is given by:

F=W-B (1)

where

W is the weight of the block (downward)

B is the buoyant force (upward)

The weight of the block is given by

W=mg

where m = 3.7 kg is the mass of the block and g=9.8 m/s^2 is the acceleration of gravity.

The buoyant force is given by

B=\rho_w V g

where

\rho_w=1000 kg/m^3 is the water density

V is the volume of the block

The volume of the block can be written as

V=\frac{m}{\rho_b}

where \rho_b=4600 kg/m^3 is the density of the block.

Substituting everything into eq.(1), we find:

F=mg-\rho_w \frac{m}{\rho_b}g=(3.7)(9.8)-(1000)\frac{1.3}{4600}(9.8)=33.4 N

2)

Here we want to find the force on the lower scale.

The force on the lower scale is equal to the difference between the total weight of the system (given by the weight of the beaker + the weight of the water + the weight of the block) and the upper net force exerted on the upper scale, therefore:

F' = m_B g + m_wg+m_b g - F

where:

m_B=1.3 kg is the mass of the beaker

m_w=2.8 kg is the mass of the water

m_b = 3.7 kg is the mass of the block

F=33.4 N is the upper net force

Substituting and solving, we find:

F'=(1.3+2.8+3.7)(9.8)-33.4=43.0 N

Learn more about forces and weight:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

6 0
3 years ago
With a class 1 lever, does mechanical advantage increase or decrease as the fulcrum is moved closer to the load? Explain why. ​
qwelly [4]

Answer:

L1 F1 = L2 F2   explains balancing torques

F1 = load = counterclockwise torque

F2 = applied force - clockwise torque

L represents distances from fulcrum to the applied forces

F2 = F1 * (L1 / L2)                (I)

MA mechanical advantage = (L2 / L1)     load over applied force

We can rewrite equation (I) as

load force / applied force = applied distance / load distance

As the fulcrum is moved closer to the load L1 decreases and L2 increases which corresponds to an increase in MA

5 0
2 years ago
Two very small 8.55-g spheres, 15.0 cm apart from center to center, are charged by adding equal numbers of electrons to each of
Leona [35]

Answer:

1.43 x 10¹⁷.

They will accelerate away from each other.

Explanation:

Force on each charged sphere F = mass x acceleration

= 8.55 x 10⁻³ x 25 x 9.8

= 2.095 N

Let Q be the charge on each sphere

F = \frac{9\times10^9\times Q^2}{(15\times10^{-2})^2}

2.095 =\frac{9\times10^9\times Q^2}{(15\times10^{-2})^2}

Q² =\frac{2.095\times(15)^2\times10^{-4}}{9\times10^9}

Q = 2.289 X 10⁻⁶

No of electrons = Charge / charge on a single electron

= \frac{2.289\times10^{-6}}{1.6\times10^{-19}}

=1.43 x 10¹³.

They will accelerate away from each other.

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3 years ago
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How many minutes are in 240 days?
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345600 minutes! hope it helps <3
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3 years ago
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