Answer:
Fs/Fm = 176.8
Explanation:
The tidal force due to a planet on earth can be given by Newton's Law of Gravitation:
F = Gm₁m₂/r²
where,
F = Tidal Force = ?
G = Gravitational Constant
m₁ = mass of 1st planet
m₂ = mass of 2nd planet
r = distance between the planets
<u>FOR TIDAL FORCE DUE TO SUN</u>:
m₁ = Mass of Earth
m₂ = Mass of Sun = 1.989 x 10³³ g
r = distance between earth and sun = 1.5 x 10⁸ km
F = Fs
Therefore,
Fs = Gm₁(1.989 x 10³³ g)/(1.5 x 10⁸ km)²
Fs = Gm₁(1.989 x 10³³ g)/(2.25 x 10¹⁶ km²)
Fs = Gm₁(8.84 x 10¹⁶ g/km²) ----- equation 1
<u>FOR TIDAL FORCE DUE TO MOON</u>:
m₁ = Mass of Earth
m₂ = Mass of Moon = 7.35 x 10²⁵ g
r = distance between earth and moon = 3.84 x 10⁵ km
F = Fm
Therefore,
Fm = Gm₁(7.35 x 10²⁵ g)/(3.84 x 10⁵ km)²
Fm = Gm₁(7.35 x 10²⁵ g)/(14.74 x 10¹⁰ km²)
Fm = Gm₁(5 x 10¹⁴ g/km²) ----- equation 2
Dividing equation 1 by equation 2 we get:
Fs/Fm = Gm₁(8.84 x 10¹⁶ g/km²)/Gm₁(5 x 10¹⁴ g/km²)
<u>Fs/Fm = 176.8</u>
B celcius to kelvin, I know this answer :) i wont troll
Change in position of object = Displacment
Uhh? Do you have any questions or need help?
