Here, Fe = Fg
q.E = m.g
We have: E = 360 V
m = 5.4 × 10⁻⁵
g = 9.8 m/s² [ constant value for earth system ]
Substitute their values into the expression:
q (360) = 5.4 × 10⁻⁵ × 9.8
q = 52.92 × 10⁻⁵ / 360
q = -1.47 × 10⁻⁶ [ negative sign represents the nature of charge ]
So, Your Final answer would be 1.47 × 10⁻⁶
Hope this helps!
Hi there!
Kinetic energy can be calculated using the following:
Where:
KE = Kinetic energy (J)
m = mass (kg)
v = velocity (m/s)
Plug in the given values:
Answer:
a. Amplitude = 0.244 meters
b. Period = 1.62 seconds
c. Frequency = 0.6173 Hz
Explanation:
a.
With the position goes from 0.122 meters to -0.122 meters (negative because it is in the opposite side of the equilibrium point), the amplitude is the maximum value minus the minimum value:
Amplitude = 0.122 - (-0.122) = 0.122 + 0.122 = 0.244 meters
b.
The period is the amount of time the object takes to arrive in the same position again. So, if it takes 0.81 seconds to go to -0.122 m, it will take another 0.81 seconds to come back to 0.122 m, so the period is the sum of these two times:
Period = 0.81 + 0.81 + 1.62 seconds
c.
The frequency of the movement is the inverse of the period:
Frequency = 1 / Period
So if the period is 1.62 seconds, the frequency is:
Frequency = 1 / 1.62 = 0.6173 Hertz
Answer:
2.63 cm
Explanation:
Hooke's law gives that the force F is equal to cy where c is spring constant and x is extension
Making c the subject of the formula then
Since F is gm but taking the given mass to be F
By substitution now considering F to be 3.3 kg
