The Ramsar Convention on Wetlands of International Importance Especially as Waterfowl Habitat is an international treaty for the conservation and sustainable use of wetlands.
Answer:
t = 2.2 [days] and is there is a round trip, it will be double time t = 4.4 [days]
Explanation:
First, we need to arrange the problem to work in the same unit system (SI).
We need to convert the 1800 [miles] to meters, therefore:
![1800[miles] * \frac{1609.34[m]}{1[mile]} }=2896812[m] = 2896.8[km]](https://tex.z-dn.net/?f=1800%5Bmiles%5D%20%2A%20%5Cfrac%7B1609.34%5Bm%5D%7D%7B1%5Bmile%5D%7D%20%7D%3D2896812%5Bm%5D%20%3D%202896.8%5Bkm%5D)
Now using the following equation of kinematics, for the avarage velocity we have:
![v=\frac{x}{t} \\where \\v=velocity [m/s]\\t = time [s]\\x=distance traveled [m]\\](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bx%7D%7Bt%7D%20%5C%5Cwhere%20%5C%5Cv%3Dvelocity%20%5Bm%2Fs%5D%5C%5Ct%20%3D%20time%20%5Bs%5D%5C%5Cx%3Ddistance%20traveled%20%5Bm%5D%5C%5C)
therefore:
![t=\frac{x}{v} \\t=\frac{2896812}{15}\\ t=193120.8[s]](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bx%7D%7Bv%7D%20%5C%5Ct%3D%5Cfrac%7B2896812%7D%7B15%7D%5C%5C%20t%3D193120.8%5Bs%5D)
Now we can convert from seconds into days.
![193120.8[s]*\frac{1[hr]}{3600[s]}*\frac{1[day]}{24[hr]}\\ t = 2.2[days]](https://tex.z-dn.net/?f=193120.8%5Bs%5D%2A%5Cfrac%7B1%5Bhr%5D%7D%7B3600%5Bs%5D%7D%2A%5Cfrac%7B1%5Bday%5D%7D%7B24%5Bhr%5D%7D%5C%5C%20%20t%20%3D%202.2%5Bdays%5D)
Now if the truck has the need to come back, the team will spend double time.
t= 4.4 [days]
solution:
When an uncharged conducting object brought near to a charged insulating object there is a force on the conducting object to move the electrons within it to opposite sides of the conductor. That means there is a separation of charges in the conducting object in the presence of the charged insulating object near to it but the charge on the conducting object is neutral.
Thus, the conducting object is uncharged.
There is a force of attraction between the uncharged conducting object and the insulating object when it brought near to the insulating object.
Thus, there is a force on the conducting object.
The conductor remains uncharged and a force is exerted on it.
