A proton enters a uniform magnetic field of strength 0.5 T at 200 m/s. The magnetic field is oriented at an angle of 30° to the

Question

4 years ago

10

proton’s velocity. What is the magnitude of the force that the proton experiences while it moves through the magnetic field?

1 answer:

-BARSIC- [3] · Answer 1 · 2022-01-03T20:29:33+03:00

<h2>The force experienced is 8 x 10⁻¹⁸ N</h2>

Explanation:

When any charge moves into the magnetic field , it experiences the force

The force can be calculated by the relation F = q v B sinθ

here q is the charge and v is its velocity .

B is magnetic field strength and θ is the angle between field and velocity vectors .

Thus F = 1.6 x 10⁻¹⁹ x 200 x 0.5 x sin 30

= 8 x 10⁻¹⁸ N