When two trains, going in opposite directions, are passing on tracks that are laid out close together, the train cars can often
2 answers:
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Answer:
v'=5.97 m/s
Explanation:
If the friction and fluid friction are ignored, then by law of conservation of mechanical energy, potential energy at the top of the slide must be equal to the kinetic energy at the bottom of the slide. Thus, the height of slide and final speed at the bottom of the slide are related as:
let the final speed be v' when h' = 2 h
The acceleration of the car is 0.5 meters per seconds square.
Given the following data:
- Initial velocity, U = 30 m/s
- Distance, S = 900 meters
Note: The final velocity (V) of the car would be zero (0) m/s when it comes to a stop.
To find the acceleration of the car, we would use the third equation of motion;
Mathematically, the third equation of motion is given by the formula;
<em>Acceleration, a </em><em>=</em><em> 0.5 </em><em></em>
Therefore, the acceleration of the car is 0.5 meters per seconds square.
Read more: brainly.com/question/8898885