A cylinder at left with balls evenly spaced throughout the cylinder has an arrow leading to a cylinder at right cylinder with ba
2 answers:
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Answer:
A) 854.46 kPa
Explanation:
P₁ = initial pressure of the gas = 400 kPa
P₂ = final pressure of the gas = ?
T₁ = initial temperature of the gas = 110 K
T₂ = final temperature of the gas = 235 K
Using the equation
Inserting the values
P₂ = 854.46 kPa
Answer:
The average velocity is
and
respectively.
Explanation:
Let's start writing the vertical position equation :
Where distance is measured in meters and time in seconds.
The average velocity is equal to the position variation divided by the time variation.
= Δx / Δt =
For the first time interval :
t1 = 5 s → t2 = 8 s
The time variation is :
For the position variation we use the vertical position equation :
Δx = x2 - x1 = 1049 m - 251 m = 798 m
The average velocity for this interval is
For the second time interval :
t1 = 4 s → t2 = 9 s
Δx = x2 - x1 = 1495 m - 125 m = 1370 m
And the time variation is t2 - t1 = 9 s - 4 s = 5 s
The average velocity for this interval is :
Finally for the third time interval :
t1 = 1 s → t2 = 7 s
The time variation is t2 - t1 = 7 s - 1 s = 6 s
Then
The position variation is x2 - x1 = 701 m - (-1 m) = 702 m
The average velocity is
The number of protons that strike the tumor each second is protons.
<u>Given the following data:</u>
- Energy of proton =
Joules.
- Current = 84 nA to A =
Ampere.
- Energy of total dose =
Joules.
<u>Scientific data:</u>
- Charge of proton =
C.
To determine the number of protons that strike the tumor each second:
<h3>How to determine the number of protons.</h3>Mathematically, the quantity of charge per unit time is given by this formula:
<u>Where:</u>
- N is the number of protons.
- t is the time measured in seconds.
- I is the current.
- e is the charge of protons.
Substituting the parameters into the formula, we have;
protons.
Read more on charges here: brainly.com/question/14372859
(a)
The frequency of an electromagnetic wave is given by:
where
is the speed of the wave in a vacuum (speed of light)
is the wavelength
In this problem, we have laser light with wavelength
. Substituting into the formula, we find its frequency:
(b) 427.6 nm
The wavelength of an electromagnetic wave in a medium is given by:
where
is the original wavelength in a vacuum (approximately equal to that in air)
is the index of refraction of the medium
In this problem, we have
n = 1.48 (index of refraction of glass)
Substituting into the formula,
(c)
The speed of an electromagnetic wave in a medium is
where c is the speed of light in a vacuum and n is the refractive index of the medium.
Since in this problem n=1.48, we find