Answer:
The acceleration that the jet liner that must have is 2.241 meters per square second.
Explanation:
Let suppose that the jet liner accelerates uniformly. From statement we know the initial (
) and final speeds (
), measured in meters per second, of the aircraft and likewise the runway length (
), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed (
), measured in meters per square second:
If we know that 
, 
and 
, then the acceleration that the jet must have is:
The acceleration that the jet liner that must have is 2.241 meters per square second.
Odpowiedź:
0,049 m / s
Wyjaśnienie:
Biorąc pod uwagę, że:
Dystans biegu = 900m
Czas trwania = 205 minut
Długość przejścia = 300 m
Zajęty czas = 205 minut
Średnia prędkość :
(Przebieg + pokonany dystans) / całkowity czas
Średnia prędkość :
(900 m +. 300 m) / 205 + 205
1200 m / 410 minut
Minuty do sekund
1200 / (410 * 60)
1200/24600
= 0,0487804
= 0,049 m / s
Answer:
1.84 hours or 110.4 minutes
Explanation:
8 miles 1.61 km 1 hr
------------ x ----------------- x -------------- = 1.84 hours or 110.4 minutes
1 mile 7 km
Answer: Work W = 0
Explanation: Work W = F·s. Because rock does not move, s = 0 and
work done is zero.
