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noname [10]
3 years ago
5

Atmospheric pressure at sea level has a value of 100kpa. The density of sea water is 1020kg/m-3. At which depth in the sea would

the total pressure be 110kpa?
Physics
1 answer:
lisov135 [29]3 years ago
6 0

Answer:

1 m

Explanation:

P = Patm + ρgh

110,000 Pa = 100,000 Pa + (1020 kg/m³) (9.8 m/s²) h

h = 1 m

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In an electronic transition an atom can not emit what?
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</span><span>In an electronic transition, an atom cannot emit what?

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When an electronic transition is occurring, an atom cannot emit ultra-violet light. 

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7 0
3 years ago
It may seem strange that the selected velocity does not depend on either the mass or the charge of the particle. (For example, w
Charra [1.4K]

Answer:

b) q large and m small

Explanation:

q is large and m is small

We'll express it as :

q > m

As we know the formula:

F = Eq

And we also know that :

F = Bqv

F = \frac{mv^{2} }{r}

Bqv = \frac{mv^{2} }{r}

or Eq = \frac{mv^{2} }{r}

Assume that you want a velocity selector that will allow particles of velocity v⃗  to pass straight through without deflection while also providing the best possible velocity resolution. You set the electric and magnetic fields to select the velocity v⃗ . To obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles) you would want to use particles with q large and m small.

6 0
3 years ago
a 4kg metal block absorbs 5000j of energy and increases to a temperature of 22°c. the metal has a specific heat capacity of 250j
e-lub [12.9K]

Answer:

17 °C

Explanation:

From specific Heat capacity.

Q = cm(t₂-t₁)................. Equation 1

Where Q = Heat absorb by the metal block, c = specific heat capacity of the metal block, m = mass of the metal block, t₂ = final temperature, t₁ = Initial temperature.

make t₁ the subject of the equation

t₁ = t₂-(Q/cm)............... Equation 2

Given: t₂ = 22 °C, Q = 5000 J, m = 4 kg, c = 250 J/kg.°c

Substitute into equation 2

t₁ = 22-[5000/(4×250)

t₁ = 22-(5000/1000)

t₁ = 22-5

t₁ = 17 °C

6 0
3 years ago
Please help !! In the diagram, q1 = +0.00200 C, q2 = 0.00180 C, and q3 = +0.00830 C. the net force on q2 is zero. how far is q2
VikaD [51]

Answer:

2.03715

Explanation:

32364=8.99\cdot 10^9\cdot \frac{0.00180\cdot 0.00830}{2.03715^2}

4 0
3 years ago
Pls help ASAP. This is astronomy but there isn't an option :)
marin [14]

From largest to smallest they are: Universe, galaxy, solar system, star, planet, moon and asteroid.

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YOUR VERY WelCoMe!!!!           :) :) :) :) :0 :)

7 0
3 years ago
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