1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vlada [557]
3 years ago
10

Can sound travel through space? Why or why not?

Physics
1 answer:
DiKsa [7]3 years ago
5 0

Answer:

I think sound does not travel at all in space. The vacuum of outer space has essentially zero air. Because sound is just vibrating air, space has no air to vibrate and therefore no sound. If you are sitting in a space ship and another space ship explodes, you would hear nothing.

Explanation:

You might be interested in
A total electric charge of 6.75 nC is distributed uniformly over the surface of a metal sphere with radius 20.0 cm. If the poten
djverab [1.8K]

Answer:

a) 60 V

b) 125 V

c) 125 V

Explanation:

<u>Given</u>

We are given the total electric charge q = 6.75 nC = 6.75x 10^-9 C distributed uniformly over the surface of a metal sphere with a radius of R = 20.0 cm = 0.020 m.  

<u>Required </u>

We are asked to calculate the potential at the distances

(a) r = 10.0 cm

(b) r = 20.0 cm

(c) r = 40.0 cm  

<u>Solution</u>

(a) Here, the distance r > R so, we can get the potential outside the sphere (r > R) where the potential is given by

V = q/4\pi∈_o                       (1)

r is the distance where the potential is measured and the term 1/4\pi∈_o equals  9.0 x 10^9 Nm^2/C^2. Now we can plug our values for q and r into equation (1) to get the potential V where r = 0.10 m  

V= 1*q/4\pi∈_o*r

 =60 V

(b) Here the distance r is the same for the radius R, so we can get the potential inside the sphere (r = R) where the potential is given by  

V = 1*q/4\pi∈_o*R                (2)    

Now we can plug our values for q and R into equation (2) to get the potential V where R = 0.20 m  

V = 1*q/4\pi∈_o*R

    = 125 V

(c) Inside the sphere the electric field is zero therefore, no work is done on a test charge that moves from any point to any other point inside the sphere. Thus the potential is the same at every point inside the sphere and is equal to the potential on the surface. and it will be the same as in part (b)  

V= 125 V

7 0
3 years ago
Scientific advances have led to decreased energy efficiency and waste reduction. please select the best answer from the choices
Andru [333]
It is false that scientific advances have led to decreased energy efficiency and waste reduction. 
3 0
3 years ago
Read 2 more answers
Suppose a soup can is made from a sheet of steel19 which is .13 mm thick. If the can is 11 cm high and 6 cm in diameter, use dif
Flura [38]

Answer:

The can mass is 0,00359 kg or 3,59 g

Explanation:

1. Relevant Data:

Steel thickness= 0.13 mm or 0.013 mm

h=11 cm

d=6 cm

ρ=800 kg/m^3

2. Calculate mass from densisty equation:

\rho=\frac{m}{v}, then m=\rho .v

We need to estimate the volume of the can to calculate the mass.

3. Estimate volume using differentials:

Cylinder volume equation is:

V=\frac{1}{4}\pi  d^{2}h

Considering that the can is an object with a hole inside, then we need to estimate the real volume of the sheet of steel.

Using differentials we have:

dV=\frac{1}{2}\pi  Dh (dD)

Then, we could say that dD=0.013 cm

Replacing the values of d, h and dD, we obtain:

dV=\frac{1}{6}\pi  (6 cm)(11 cm)(0,013 cm)

dV=0,4492 cm^3

4. Calculate the mass

Convert volume unit into m^3

0,4492 cm^3x\frac{1 m^3}{1x10^6 cm^3} =0,4492 x 10^-6 m^3

Calculate mass

m=\rho .v

m=8000 \frac{kg}{m^3}.0,4492 x10^-6 m^3

m=0,00359 kg =3,59 g

5 0
4 years ago
If the mass of an object on earth is 40 kilograms it’s mass on the moon is
g100num [7]
Speaking bout mass,
it's mass is still 40Kg on the moon

but it's Weight on the moon is 1/6mg
5 0
4 years ago
A roundabout is a type of playground equipment involving a large flat metal disk that is able to spin about its center axis. A r
Zina [86]

Answer:

116.1 kgm²/s

1.12718 rad/s

Decreases

Explanation:

m = Mass of girl = 43 kg

M = Mass of roundabout = 120 kg

v = Velocity of roundabout = 2.7 m/s

r = Radius of roundabout = 1 m = R

I = Moment of inertia

Her angular momentum

L_i=mvr\\\Rightarrow L_i=43\times 2.7\times 1\\\Rightarrow L_i=116.1\ kgm^2/s

Magnitude of angular momentum is 116.1 kgm²/s

Here the angular momentum is conserved

L_f=L_i\\\Rightarrow I\omega=L_i\\\Rightarrow (\frac{1}{2}MR^2+mr^2)\omega=116.1\\\Rightarrow \omega=\frac{116.1}{\frac{1}{2}\times 120\times 1^2+43\times 1^2}\\\Rightarrow \omega=1.12718\ rad/s

Angular speed of the roundabout is 1.12718 rad/s

Initial kinetic energy

K_i=\frac{1}{2}mv^2\\\Rightarrow K_i=\frac{1}{2}43\times 2.7^2\\\Rightarrow K_i=156.735\ J

Final kinetic energy

K_f=\frac{1}{2}I\omega^2\\\Rightarrow K_f=\frac{1}{2}\times (\frac{1}{2}\times 120\times 1^2+43\times 1^2)\times 1.12718^2\\\Rightarrow K_f=65.43253\ J

The overall kinetic energy decreases as can be seen. This loss is converted to heat.

5 0
3 years ago
Other questions:
  • What is analogy a powerful rhetorical device?
    5·1 answer
  • An average person can reach a maximum height of about 65 cm when jumping straight up from a crouched position. During the jump i
    14·1 answer
  • Name three ways electricity can be produced.​
    8·1 answer
  • Cuántas veces es mayor la masa del protón que la del electrón?
    5·1 answer
  • Why do you think people believe some theories even if they are not supported by credible evidence
    15·2 answers
  • How does energy travel? Where is the initial source of energy in our solar system? What is the process that gives off energy fro
    8·1 answer
  • How do u find the number of electronic
    5·1 answer
  • Model a hydrogen atom as a three-dimensional potential well with Uo = 0 in the region 0 &lt; x a. 283 eV <br> b. 339 eV <br> c.
    9·1 answer
  • A diver jumps off a 60 m cliff with an initial horizontal velocity of 3m/s. Find
    13·1 answer
  • An experiment is performed to determine the force constant k of a spring by measuring its length as a function of the applied lo
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!